在找不到符合我需求的任何内容后,我编写了这段代码,以便在mysql中一致地改变列的值。有更好的方法吗?
**Original table:**
+----+-----------+
| id | fname |
+----+-----------+
| 1 | mike |
| 2 | ricky |
| 3 | jane |
| 4 | august |
| 6 | dave |
| 9 | Jérôme |
+----+-----------+
**Possible output:**
+----+-----------+
| id | fname |
+----+-----------+
| 1 | dave |
| 2 | jane |
| 3 | mike |
| 4 | ricky |
| 6 | Jérôme |
| 9 | august |
+----+-----------+
DROP TEMPORARY TABLE IF EXISTS shuffle1;
DROP TEMPORARY TABLE IF EXISTS shuffle2;
CREATE TEMPORARY TABLE shuffle1 (id int(11) NOT NULL AUTO_INCREMENT, PRIMARY KEY (id), original_values varchar(255), key original_values(original_values) );
CREATE TEMPORARY TABLE shuffle2 (id int(11) NOT NULL AUTO_INCREMENT, PRIMARY KEY (id), original_ids int(11), key original_ids(original_ids) );
INSERT INTO shuffle1 (id, original_values) SELECT NULL, table1.fname FROM table1 ORDER BY rand();
INSERT INTO shuffle2 (id, original_ids) SELECT NULL, table1.id FROM table1;
UPDATE table1 SET table1.fname = (SELECT shuffle1.original_values FROM shuffle1 JOIN shuffle2 ON shuffle2.id = shuffle1.id WHERE table1.id = shuffle2.original_ids);
答案 0 :(得分:0)
如果您不介意某些表数据无法处理(取决于表大小,预计无法处理50%的行),请采用以下解决方案:
id name
1 Some
2 Body
3 Once
4 Told
5 Me
6 The
7 World
8 Is
9 Gonna
10 Roll
11 Me
12 I
13 Ain't
14 The
15 Shapest
16 Tool
17 In
18 The
19 Shed
20 She
21 was
22 looking
23 kind
24 of
25 dumb
26 with
27 her
28 finger
29 and
30 her
31 thumb
SELECT new_id, name FROM (
SELECT new_id, name FROM (
SELECT new_meme.id as new_id, original_meme.id as original_id, original_meme.name FROM meme original_meme
JOIN meme new_meme ON new_meme.id <> original_meme.id
ORDER BY RAND()
) layer1
GROUP BY layer1.new_id
) layer2 GROUP BY name
1 I
2 In
3 Gonna
4 Ain't
5 The
6 her
7 finger
8 Some
9 dumb
10 She
15 Me
16 with
17 Told
18 and
19 World
21 Roll
22 The
25 Tool
26 Shed
27 Is
28 Me
29 Sharpest
31 The
注意:您可能会发现查询非常慢,这是因为它两次连接了表,因此如果数据大小为1000,则需要处理1000 * 1000。
您可以通过将ON new_meme.id <> original_meme.id
切换为ON new_meme.id BETWEEN original_meme.id - 5 AND original_meme.id +5
(可以更改5)来控制查询的速度,但是它将降低随机性,不适用于非数字ID
答案 1 :(得分:-1)
UPDATE table1 SET fname=(SELECT t.fname FROM(SELECT fname FROM table1) t ORDER BY RAND() LIMIT 1)