如何在两个表中混淆帖子?

时间:2015-04-04 20:32:32

标签: php mysql pdo

我正在研究一个邮政系统..
因此,我必须显示用户的朋友和用户参与的组的帖子。
这是我展示帖子的代码..

<?php
  $sql = "SELECT * FROM posts WHERE uploader_id=:friend_id ORDER BY id DESC";
  $query = $db->prepare($sql);
  $query->execute(array(
     ":friend_id" => $friend_id
  ));
  $rows = $query->fetchAll(PDO::FETCH_ASSOC);
  foreach ($rows as $row) {
      $name = $row['name'];
      echo "POST BY $name";
  }
  $sql = "SELECT * FROM group_posts WHERE id=:member_group ORDER BY id DESC";
  $query = $db->prepare($sql);
  $query->execute(array(
     ":member_group" => $group_id
  ));
  $rows = $query->fetchAll(PDO::FETCH_ASSOC);
  foreach ($rows as $row) {
     $name = $row['name'];
     echo "POST BY $name";
  }
?>

现在,我希望所有这些帖子都以一种方式进行洗牌,即post表和group_posts表的所有帖子都按降序显示。

更新

我编辑了我的代码..
我发现首先我必须在编写邮政系统之前对其进行编码..

<?php
  $sql = "SELECT * FROM friends WHERE user_one=:me OR user_two=:me2 UNION SELECT * FROM group_members WHERE member_id=:me3";
  $query = $db->prepare($sql);
  $query->execute(array(
      ":me" => $my_id,
      ":me2" => $my_id,
      ":me3" => $my_id
  ));
  $rows = $query->fetchAll(PDO::FETCH_ASSOC);
  foreach ($rows as $row) {
     $user_one = $row['user_one'];
     $user_two = $row['user_two'];
     $group_id = $row['group_id'];
     if ($user_one == $my_id) {
         $friend_id = $user_two;
     } else {
         $friend_id = $user_one;
     }
     echo $friend_id . "<BR>" . $group_id;
  }
?>

现在,问题就在这里...... 这是成功打印$ friend_id但是,它显示了一个未定义的索引&#39; group_id&#39;同时打印$ group_id 我检查过所有字段都是正确的。

1 个答案:

答案 0 :(得分:0)

尝试仅使用UNION

的一个查询
SELECT *
FROM (
  SELECT name, id FROM posts WHERE uploader_id=:friend_id
  UNION
  SELECT name, id FROM group_posts WHERE id=:member_group
) p
ORDER BY p.id DESC

请注意,您的内部查询必须以相同的顺序返回相同列数(并且我认为也使用相同的名称/别名)。