Question

这是我的Json代码

[
{"ProspectID":"87f3278e-c9ee-4775-abc6-4813969d45a5",
"FirstName":"erter",
"LastName":"nurtertel",
"EmailAddress":"null",
"Company":"null",
"Phone":"null",
"Mobile":"456456456",
"Total":"690"},

{"ProspectID":"00969dcd-5c03-450e-832c-063e976285d5",
"FirstName":"rter",
"LastName":"erte",
"EmailAddress":"null",
"Company":"null",
"Phone":"56456456",
"Mobile":"null",
"Total":"690"}
]

在这段代码中我需要获取那个prospectID.how来获取数组php代码中的那个prospectID吗？

Answer 1

[]是一个数组，{}是一个Javascript对象。

如果你从Ajax调用中将它变成一个变量，例如jsonData，你的库应该解析该字符串，将其转换为Javascript数组和对象。检查您的库文档，您可能必须指定响应的格式（'json'）。

完成此操作后，您只需访问prospectID.how，如下所示：

var jsonData = your parsed string;
alert('ProspectID of first item is: ' + jsonData[0].ProspectID);
alert('ProspectID of second item is: ' + jsonData[0].ProspectID);

显然，您也可以使用for..loop

迭代数组

Answer 2

首先你需要改变你的json字符串。

将" "置于null。

使用以下代码获取'ProspectID'

的值

$json = '[{"ProspectID":"87f3278e-c9ee-4775-abc6-4813969d45a5","FirstName":"erter","LastName":"nurtertel","EmailAddress":"null","Company":"null","Phone":"null","Mobile":"456456456","Total":"690"},{"ProspectID":"00969dcd-5c03-450e-832c-063e976285d5","FirstName":"rter","LastName":"erte","EmailAddress":"null","Company":"null","Phone":"56456456","Mobile":"null","Total":"690"}]';
$data = json_decode($json);
for($i=0; $i<count($data); $i++ ){
$ProspectID =   $data[$i]->{'ProspectID'};
echo $ProspectID."<br>";
}

从Json代码中获取值

2 个答案: