从字典中查找包含多个单词的术语

Question

所以我正在做一个项目，我从文件中找到单词，然后检查它是否在字典中。我不知道我是否遵循正确的语法，因为它打印出在字典中找不到“不起作用”的else语句。 它与中间的空格有什么关系吗？

测试多个单词的术语 - 不起作用：-3

if 'does not work' in dictionary:
    expected_value3 = str(-3)
    actual_value3 = dictionary['does not work']
    if actual_value3 == expected_value3:
        print "---------------------------------"
        print "words with spaces passes| word: does not work"
    else:
        print "---------------------------------"
        print "words with spaces FALSE| word: does not work"
else:
    print "---------------------------------"
    print "does not work not in dictionary"

Answer 1

要处理短语，您无法在格式word def的字典文件中按空格分割一行，因为word可能由多个带空格的单词组成在两者之间。你需要有一个不会出现在word或def中的字符来分隔它们，例如标签\t或管道|，然后像你的字典一样构建你的字典这样：

d = {}
with open('dict.txt') as df:
    for line in df:
        word,definition = line.split('\t')
        d[word] = definition

否则你最终会

sentiments = ['does','not','work','the','operation',...]

在你的循环中，你最终设置

dictionary['does'] = 'not'

使用代码

for line in scores_file:
    sentiments = line.split()
    dictionary[sentiments[0]] = sentiments[1]