Question

这是我的异步代码

@Override
protected SoapObject doInBackground(String... params) {
try {
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
    request.addProperty("ID", "0014");
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                    SoapEnvelope.VER11);
    envelope.setOutputSoapObject(request);
    envelope.implicitTypes = false;
    envelope.dotNet = true;
    HttpTransportSE transport = new HttpTransportSE(URL);

try {
    transport.call(SOAP_ACTION, envelope);
} catch (Exception e) {
    e.printStackTrace();
}
try {
    SoapFault fault = (SoapFault) envelope.bodyIn;
    System.out.println("fault in getdata : " + fault);
} catch (Exception e) {
    e.printStackTrace();
}
try {
    result = (SoapObject) envelope.bodyIn;
    System.out.println("result in getdata : " + result);
} catch (Exception e) {
    e.printStackTrace();
}
    } catch (Exception e) {
        // System.out.println("Exception : " + e.toString());
    }
    return result;
    }

我的回答是

result in getdata : Getesponse{GetResult=anyType{schema=anyType{element=anyType{complexType=anyType{choice=anyType
{element=anyType{complexType=anyType{sequence=anyType{element=anyType{}; element=anyType{}; element=anyType{}; 
element=anyType{}; element=anyType{}; element=anyType{}; element=anyType{}; }; }; }; }; }; }; }; 
diffgram=anyType{DocumentElement=anyType{Table1=anyType{Name=Sathish1; Subject=anyType{}; ID=0014; }; }; }; }; }

我希望主题为null而不是anyType{}。除了使用if语句朋友查看之外，还有更好的想法吗？

Answer 1

稍后解析结果时，请使用getPrimitiveProperty代替getProperty。它本质上是相同的，但修复了这种错误。

Answer 2

字符串代码= soapObject.getProperty（“Code”）。toString（）。replace（“anyType {}”，“”）;

Answer 3

要获得回复，最好使用：

SoapObject result = (SoapObject) envelope.getResponse();

或者其他方式，但您需要事先启用调试：

androidHttpsTransport.debug = true;

这是我如何打电话并得到答复：

private String makeCall(SoapSerializationEnvelope envelope) {
    HttpsTransportSE mHttpsTransport = getAndroidHttpsTransport();

    try {
        mHttpsTransport.call(SOAP_ACTION, envelope);
    } catch (IOException e) {
        Logger.logError(TAG, e);
    } catch (XmlPullParserException e) {
        Logger.logError(TAG, e);
    } finally {
        Logger.logDebug(TAG, "Request dump is ");
    }

    return mHttpsTransport.responseDump;
}

Ksoap2返回anytype {}而不是null

3 个答案: