我在我的Android应用程序中调用了一个Web服务&方法是getGramaNiladhariData(), 我得到的结果是SoapObject。
result = (SoapObject) envelope.bodyIn; Log.d("WS", String.valueOf(result));
这就是我为 String.valueOf(结果)
所获得的这里我调用的方法返回一个complexType对象,由5个属性组成。 正如我在互联网上发现的那样,我无法获得soap对象作为返回complexType对象的webservice方法的结果。如果是这样,我应该如何获取值。
我想要解决的是为什么我得到anyType {},作为值,而不是实际值。 任何帮助将不胜感激
答案 0 :(得分:5)
回答太迟了。但是我和其他认为有用的人,
通过执行String.valueOf(result)
,您将打印身体的全部内容。但是为了使用参数获取您的值,首先您需要点击以更正SoapObject
。
我不知道是否有任何简单的方法可以找到正确的SoapObject
,但仍然可以这样做,一旦你得到了正确的SoapObject
,那么你就完成了。在下面找到如何找到正确的SoapObject
,
首先,您需要检查第一个SoapObject
中的参数数量,
result.getPropertyCount();
你会得到更少的数量,因为这是第一个封面,
然后,打印并查看哪个param为您提供了核心信息,
result.getProperty(0);
result.getProperty(1);
etc ...
找到正确的参数后,抓住SoapObject
。像这样,
SoapObject result2 = (SoapObject) result.getProperty(0);
然后检查此对象的计数。并执行与上述相同的操作,直到获得正确的SoapObject
。
找到最后一个SoapObject
后,它会像这样打印而没有无用的字符串,
anyType{gnName = Prasad; address = Address of the person; ; workingDays = 5; gnDivision = California; contactNumber = 0123456789}
现在你可以像这样继续使用这个对象,
SoapObject result3 = (SoapObject) result2.getProperty(5);
Log.v("Name : ", result3.getProperty("gnName").toString());
您将获得DDMS中的输出,如下所示,
Name : Prasad
我想这会对你有帮助,如果你有任何进一步的问题,请告诉我。
答案 1 :(得分:1)
我制作自己的代码我刚刚完成它我想与你分享它可能会帮助一些
我只与一张桌子一起工作,这对我有用 我将尝试解释步骤
try {
// Invole web service
androidHttpTransport.call(SOAP_ACTION + "mywebservicecall", envelope);
// Get the response
SoapObject resultsString = (SoapObject) envelope.getResponse();
//resultsString looks like this ==> anyType{schema=anyType{element=anyType{complexType=anyType{choice=anyT....etc
//here i found some complex in getproperty(0) so i not need it
//then i make Object1 that contain datatable from my database getproperty(1)
SoapObject Object1 = (SoapObject) resultsString.getProperty(1);
//object1 look like this ==> anyType{NewDataSet=anyType{Table1=anyType{ID_CAT=1; CAT_V_N=ma
//here my table1 i wanna to fitch the NewDataSet
SoapObject tables = (SoapObject) Object1.getProperty(0); //NewDataset
//tables object now looks like this ==> anyType{Table1=anyType{ID_CAT=1;CAT_N ...etc
//now i wanna loop in my table to get columns valus it will be tablesObject properties depend on iteration to get row by row
for (int i = 0; i < tables.getPropertyCount(); i++) {
SoapObject Objecttable = (SoapObject) tables.getProperty(i);
System.out.println("ID_CAT = " + Objecttable.getProperty("ID_CAT").toString());
System.out.println("CAT_N= " +Objecttable.getProperty("CAT_N").toString());
}
} catch (Exception e) {
e.printStackTrace();
System.out.println("ID_CAT = 0 ");
System.out.println("CAT_N = None");
}
最后一段代码解释一个表
现在我刚刚结束的是如何控制多表
我也会解释它
SoapObject resultsString = (SoapObject) envelope.getResponse();
// the same
SoapObject Object1 = (SoapObject) resultsString.getProperty(1);
// the same
SoapObject tables = (SoapObject) Object1.getProperty(0);
// the same
// the same
for(int i = 0; i < tables.getPropertyCount(); i++){
SoapObject Objecttable = (SoapObject) (SoapObject) tables.getProperty(i);
try{
//tables.toString().substring(8,tables.toString().indexOf("=")).equals("Table1")
// here i was try to get the name of the table to hundel it but i fount my table name in attribute id
// it not came as table name like if my table that comming from database is hi
//the first row will be attrib=>id=>hi1 and sec row will be hi2
//the first row will be attrib=>rowOrder=>0 and sec row will be 1
if(Objecttable.getAttribute("id").equals("Table1"+(Integer.valueOf(Objecttable.getAttribute("rowOrder").toString())+1))){
// so Objecttable.getAttribute("id") will be ( "Table11" ) in first row
//Objecttable.getAttribute("rowOrder").toString() ==> will be 0
//Integer.valueOf(Objecttable.getAttribute("rowOrder").toString())+1) well be 1 for first row of this table
// so Objecttable.getAttribute("id").equals("Table1"+(Integer.valueOf(Objecttable.getAttribute("rowOrder").toString())+1)) will be true
/**
then i can loop and fitch data like single table
*/
}
if(Objecttable.getAttribute("id").equals("Table2"+(Integer.valueOf(Objecttable.getAttribute("rowOrder").toString())+1))){
}
}catch (Exception e) {
}
希望你们好运好运
答案 2 :(得分:0)
anytype {}。首先插入一些数据,然后尝试从Web服务获取数据。
答案 3 :(得分:-1)
我以前遇到过这个问题。我解决了它。我以前遇到过这个问题。我解决了它。我似乎花了很多时间来找到解决这个问题的方法。我的项目是它的工作。我创建了Web Service .Net Object Array。我希望这会对你有所帮助。
//.................................
SoapObject requestx = new SoapObject(NAMESPACE, METHOD_NAME);
SoapSerializationEnvelope envelopex = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelopex.dotNet = true;
envelopex.setOutputSoapObject(requestx);
HttpTransportSE httpTransportx = new HttpTransportSE(URL);
try {
httpTransportx.call(SOAP_ACTION, envelopex);
SoapObject responsex = (SoapObject)envelopex.getResponse(); // not envelopex.bodyIn;
int i=0;
int RCount=responsex.getPropertyCount();
int[] tbIDArray = new int[RCount+1];
int[] iMonthAarray = new int[RCount+1];
int[] iYearAarray = new int[RCount+1];
String[] sDetailAarray = new String[RCount+1];
for (i = 0; i < RCount; i++) {
Object property = responsex.getProperty(i);
if (property instanceof SoapObject) {
SoapObject info = (SoapObject) property;
String tbID = info.getProperty("tbID").toString();
String iMonth = info.getProperty("iMonth").toString();
String iYear = info.getProperty("iYear").toString();
String sDetail = info.getProperty("sDetail").toString();
tbIDArray[i] =Integer.valueOf(tbID);
iMonthAarray[i] =Integer.valueOf(iMonth);
iYearAarray[i] =Integer.valueOf(iYear);
sDetailAarray[i] =sDetail;
}//if (property instanceof SoapObject) {
}//for (i = 0; i < RCount; i++) {
} catch (Exception exception) {
MsgBox1(exception.toString() , "Error");
}