我有一个包含非标准字符的XML文件(比如奇怪的“引用”)。
我使用UTF-8 / ISO / ascii + unmarshalled读取XML:
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream()),"ISO-8859-1"));
String output;
StringBuffer sb = new StringBuffer();
while ((output = br.readLine()) != null) {
//fetch XML
sb.append(output);
}
try {
jc = JAXBContext.newInstance(ServiceResponse.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
ServiceResponse OWrsp = (ServiceResponse) unmarshaller
.unmarshal(new InputSource(new StringReader(sb.toString())));
我有一个oracle函数,它将采用iso-8859-1代码,并将它们转换/映射为“literal”符号。即:“&#x2019”=> “左单引号”
使用iso的JAXB unmarshal,显示iso转换精细的字符。即所有奇怪的单引号都将被编码为“&#x2019”
所以假设我的字符串是:10-11岁的班级(注意奇怪 - 介于11和年之间)
jc = JAXBContext.newInstance(ScienceProductBuilderInfoType.class);
Marshaller m = jc.createMarshaller();
m.setProperty(Marshaller.JAXB_ENCODING, "ISO-8859-1");
//save a temp file
File file2 = new File("tmp.xml");
这将保存在文件中:
class of 10–11‐year‐olds. (what i want..so file saving works!)
[旁注:我已经使用java文件阅读器读取了文件,并且输出上面的字符串很好]
我遇到的问题是使用jaxb unmarshaller的STRING表示具有奇怪的输出,由于某种原因我似乎无法获得表示的字符串 - 。
当我 1:检查xml unmarshalled输出:
class of 10?11?year?olds
2:文件输出:
class of 10–11‐year‐olds
我甚至尝试从保存的XML中读取文件,然后解组(希望在我的字符串中获取 - )
String sCurrentLine;
BufferedReader br = new BufferedReader(new FileReader("tmp.xml"));
StringBuffer sb = new StringBuffer();
while ((sCurrentLine = br.readLine()) != null) {
sb.append(sCurrentLine);
}
ScienceProductBuilderInfoType rsp = (ScienceProductBuilderInfoType) unm
.unmarshal(new InputSource(new StringReader(sb.toString())));
无济于事。
如何在jaxb中获取iso-8859-1编码字符?
答案 0 :(得分:0)
解决:使用stackoverflow上找到的这个tibid代码
final class HtmlEncoder {
private HtmlEncoder() {}
public static <T extends Appendable> T escapeNonLatin(CharSequence sequence,
T out) throws java.io.IOException {
for (int i = 0; i < sequence.length(); i++) {
char ch = sequence.charAt(i);
if (Character.UnicodeBlock.of(ch) == Character.UnicodeBlock.BASIC_LATIN) {
out.append(ch);
} else {
int codepoint = Character.codePointAt(sequence, i);
// handle supplementary range chars
i += Character.charCount(codepoint) - 1;
// emit entity
out.append("&#x");
out.append(Integer.toHexString(codepoint));
out.append(";");
}
}
return out;
}
}
HtmlEncoder.escapeNonLatin(MyString的)