如何删除长文本中某个字符附近的一个或多个空格。我不想删除与匹配字符串相邻的其他空格。我只想删除匹配字符旁边的所有空格而不是输入字符串的所有空格。例如:
[text][space][space]![space][text] should result in [text]![text]
[text][space][space]![space][space][space][text] should result in [text]![text]
[text][space]![space][space][text] should result in [text]![text]
[text][space]![space][text] should result in [text]![text]
[text]![space][space][text] should result in [text]![text]
[text][space][space]![text] should result in [text]![text]
[text][space][space]! should result in [text]!
![space][space][text] should result in ![text]
我要写的代码是:
for (int i = 0 to length of string)
{
if (string[i] == character) //which is the desired character "!"
{
int location = i+1;
//remove all whitespace after the character till a non-whitespace character
//is found or string ends
while (string[location] == whitespace)
{
string[location].replace(" ", "");
location++;
}
int location = i-1;
//remove all whitespace before the character till a non-whitespace character
//is found or string ends
while (string[location] == whitespace)
{
string[location].replace(" ", "");
location--;
}
}
}
使用正则表达式删除字符附近的空格是否有更好的方法?
更新:我不想删除与匹配字符串相邻的其他空格。例如:
some_text[space]some_other_text[space][space]![space]some_text[space]some_other_text
is
some_text[space]some_other_text!some_text[space]some_other_text
答案 0 :(得分:4)
Regex rgx = new Regex(pattern);
string input = "This is text with far too much " +
"whitespace.";
string pattern = "\\s*!\\s*";
string replacement = "!";
Regex rgx = new Regex(pattern);
string result = rgx.Replace(input, replacement);
取自http://msdn.microsoft.com/de-de/library/vstudio/xwewhkd1.aspx