Question

如何删除非字母数字字符之间的空格？例如

anti - C6 / 36 membrane antibodies 
D2 NS1 - P1 - specific antibodies

要

anti-C6/36 membrane antibodies 
D2 NS1-P1-specific antibodies

Answer 1

您可以将此基于外观的正则表达式用于搜索：

(?<![\p{L}\p{N}]) +| +(?![\p{L}\p{N}])

并用空字符串替换它。

RegEx Demo

在Java中：

String repl = input.replaceAll( "(?<![\\p{L}\\p{N}]) +| +(?![\\p{L}\\p{N}])", "" );

(?<![\p{L}\p{N}]) | (?![\p{L}\p{N}])表示如果空格后面没有字母数字或者前面没有字母数字，则匹配空格。

Answer 2

(?<=\W)[ ]+|[ ]+(?=\W)

试试这个。empty string。见。演示。

https://regex101.com/r/zB3hI5/11

对于java，它将是

(?<=\\W)[ ]+|[ ]+(?=\\W)

Answer 3

尝试使用这样的正则表达式：

public static void main(String[] args) {
    String s1 = "anti - C6 / 36 membrane antibodies";
    String s2 = "D2 NS1 - P1 - specific antibodies";
    String pattern = "\\s+(?=[^a-zA-Z0-9]+)|(?<=[^a-zA-Z0-9])\\s+";// replace all spaces either preceeded by or followed by a non-alphanumeric character
    System.out.println(s1.replaceAll(pattern, ""));
    System.out.println(s2.replaceAll(pattern, ""));
}

O / P：

anti-C6/36 membrane antibodies
D2 NS1-P1-specific antibodies

删除非字母数字字符之间的空格

3 个答案: