使用矢量控制显示输出

时间:2013-08-12 17:10:15

标签: c++ if-statement for-loop vector cout

矢量大小:2

矢量数据:Carol Mary

if(vector.size() >=2)
{
    cout<<vector.size();

    for(int i=1;i<vector.size()-2;i++)
    {
        cout<<" AND ";
    }
}

输出显示:Carol AND Mary AND

如何将其更改为Carol AND Mary?

当我的矢量大小为3时,

如何将其更改为Carol AND Mary AND Peter

提前致谢!

4 个答案:

答案 0 :(得分:3)

假设向量名为v。

if(!v.empty()) {
  cout << v[0];
  for(int i = 1; i<v.size(); ++i) {
    cout << " AND " << v[i];
  }
}

答案 1 :(得分:1)

我会使用我的infix_ostream_iterator

std::copy(vec.begin(), vec.end(), 
         infix_ostream_iterator<std::string>(std::cout, " AND "));

infix_ostream_iterator代码位于CodeReview.SE

答案 2 :(得分:1)

只是添加我喜欢的方式:

const char *sep = "";
for (size_t i=0; i<vec.size(); ++i, sep=" AND ")
    cout << sep << vec[i];
cout << endl;

或者,甚至更短:

cout << join(vec, " AND ") << endl;

也就是说,使用boost :: algorithm :: join(),就像Python(" AND ".join(vec))一样。

答案 3 :(得分:0)

std::vector<std::string> vec {"Carol","Marry","Peter"};

int i=1;
std::cout<<vec[0];

for(;i<vec.size();++i)
  std::cout<<" AND "<<vec[i];