Question

我想用XML内容类型编写请求的主体，但我不知道如何使用HttpClient对象（http://hc.apache.org/httpclient-3.x/apidocs/index.html）

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpRequest = new HttpPost(this.url);
httpRequest.setHeader("Content-Type", "application/xml");

我不知道如何继续使用我的XML编写正文......

Answer 1

如果您的xml是由java.lang.String撰写的，那么您可以这样使用HttpClient

    public void post() throws Exception{
        HttpClient client = new DefaultHttpClient();
        HttpPost post = new HttpPost("http://www.baidu.com");
        String xml = "<xml>xxxx</xml>";
        HttpEntity entity = new ByteArrayEntity(xml.getBytes("UTF-8"));
        post.setEntity(entity);
        HttpResponse response = client.execute(post);
        String result = EntityUtils.toString(response.getEntity());
    }

注意例外。

BTW，该示例由httpclient版本4.x

编写

Answer 2

扩展您的代码（假设您要发送的XML位于xmlString）：

String xmlString = "</xml>";
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpRequest = new HttpPost(this.url);
httpRequest.setHeader("Content-Type", "application/xml");
StringEntity xmlEntity = new StringEntity(xmlString);
httpRequest.setEntity(xmlEntity );
HttpResponse httpresponse = httpclient.execute(httppost);

使用HttpClient写入正文请求

2 个答案: