Question

我想用HttpClient以下面的格式发出请求：头：

X-Requested-With: XMLHttpRequest
User-Agent: .....  //etc.

重要的部分是让我困惑的请求体：

{"jsonrpc":"2.0","method":"getPostList","id":1,"params":[[["place2",0,["10"]]],0]}

我做了一些像这样的代码：

HttpClient h = new HttpClient();

h.DefaultRequestHeaders.Add("X-Requested-With","XMLHttpRequest");
h.DefaultRequestHeaders.Add("User-Agent", "Mozilla/5.0 (Windows NT 6.2; WOW64; rv:33.0) Gecko/20100101 Firefox/33.0");
h.DefaultRequestHeaders.Add("Referer","http://urmia.divar.ir/browse/");
h.DefaultRequestHeaders.Add("Pragma","no-cache");
h.DefaultRequestHeaders.Add("Host","urmia.divar.ir");
//h.DefaultRequestHeaders.Add("Content-Type","application/json; charset=UTF-8");
h.DefaultRequestHeaders.Add("Connection","keep-alive");
h.DefaultRequestHeaders.Add("Accept-Language","en-US,en;q=0.5");
h.DefaultRequestHeaders.Add("Accept-Encoding","gzip, deflate");
h.DefaultRequestHeaders.Add("Accept","application/json, text/javascript, */*; q=0.01");

var request = new HttpRequestMessage(HttpMethod.Post, "http://urmia.divar.ir/json/");

request.Content.Headers.AddWithoutValidation("jsonrpc","2.0");
request.Content.Headers.Add("method", "getPostList");
request.Content.Headers.Add("id", "1");
request.Content.Headers.Add("params", "[[[\"place2\",0,[\"10\"]]],0]");

但它为request.Content.Headers.add ....

提供了错误

Answer 1

不知道那个请求会返回什么 - 但它似乎是二元的...... 这就是我设法得到回应的方式 - 无论它是什么:) 因此，如示例代码所示，我将JSON请求对象放入请求消息的正文中。

using System.Text;
using System.Threading.Tasks;
using System.Net;
using System.Net.Http;
using System.Net.Http.Headers;
using System.IO;

namespace CSharpQuestions
{
    class Program
    {
        static Stream GenerateStreamFromString(string s)
        {
            MemoryStream stream = new MemoryStream();
            StreamWriter writer = new StreamWriter(stream);
            writer.Write(s);
            writer.Flush();
            stream.Position = 0;
            return stream;
        }

        static void Main(string[] args)
        {
            HttpClient h = new HttpClient();

            h.DefaultRequestHeaders.Add("X-Requested-With", "XMLHttpRequest");
            h.DefaultRequestHeaders.Add("User-Agent", "Mozilla/5.0 (Windows NT 6.2; WOW64; rv:33.0) Gecko/20100101 Firefox/33.0");
            h.DefaultRequestHeaders.Add("Referer", "http://urmia.divar.ir/browse/");
            h.DefaultRequestHeaders.Add("Pragma", "no-cache");
            h.DefaultRequestHeaders.Add("Host", "urmia.divar.ir");
            // h.DefaultRequestHeaders.Add("Content-Type","application/json; charset=UTF-8");
            h.DefaultRequestHeaders.Add("Connection", "keep-alive");
            h.DefaultRequestHeaders.Add("Accept-Language", "en-US,en;q=0.5");
            h.DefaultRequestHeaders.Add("Accept-Encoding", "gzip, deflate");
            h.DefaultRequestHeaders.Add("Accept", "application/json, text/javascript, */*; q=0.01");

            string myJSONRequest = "{\"jsonrpc\":\"2.0\",\"method\":\"getPostList\",\"id\":1,\"params\":[[[\"place2\",0,[\"10\"]]],0]}";
            HttpContent requestContent = new StreamContent(GenerateStreamFromString(myJSONRequest));
            Task<HttpResponseMessage> response = h.PostAsync("http://urmia.divar.ir/json/", requestContent);
            response.Wait(3000);
            byte[] responseText = response.Result.Content.ReadAsByteArrayAsync().Result;
            System.Console.WriteLine(responseText); // you would know what to do with the data ;)

        }

    }
}

使用请求标头和正文生成HttpClient Request visual c＃

1 个答案: