我在Android应用中实现了以下代码,该代码拆分从SQL检索到的日期/时间值,并显示自收到消息以来的分钟/小时数:
//Splits the date and time string retrieved from SQL into two separate strings,
//and stores them into an array
String[] dt_array = m1.getTime().split(" ");
//String date = dt_array[0];
String time = dt_array[1];
//Splits the time into two strings, one for hours and one for minutes, and stores them
//into an array
String[] timeSplit = time.split(":");
String hourString = timeSplit[0];
String minuteString = timeSplit[1];
//converts the new separate time strings to integer variables
int msgHour = Integer.parseInt(hourString);
int msgMinute =Integer.parseInt(minuteString);
Calendar currentTime = Calendar.getInstance();
//retrieves current hour and minute from device and stores in separate ints
int currentHour = currentTime.get(Calendar.HOUR);
int currentMinute = currentTime.get(Calendar.MINUTE);
int hoursSince;
int minutesSince;
String timeDisplay = null;
if (currentHour != 1)
{
//tells app to display minutes if message was received under an hour ago
if(currentHour - msgHour < 1)
{
minutesSince = currentMinute - msgMinute;
//if only a minute has passed, text should read "1 minute ago", otherwise use plural "minutes"
if (minutesSince == 1)
timeDisplay = minutesSince + " minute ago";
else
timeDisplay = minutesSince + " minutes ago";
}
else if (currentHour - msgHour >= 1)
{
hoursSince = currentHour - msgHour;
timeDisplay = hoursSince + " hours ago";
}
}
else
{
//for messages that were received at a 12th hour, if the hour is currently 1, correctly displays 1 hour ago
if(msgHour == 12 && currentHour == 1)
{
hoursSince = 1;
timeDisplay = hoursSince + " hours ago";
}
}
我想要的是添加一个功能,如果小时数超过24,则会显示收到的天数。我知道这应该很简单,但我不确定如何在Android上进行此操作。
答案 0 :(得分:1)
确定自邮件发布以来的时间量的方法过于复杂,并且在分钟和小时翻转时容易出现问题。这样的事情会简单得多:
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy HH:mm"); //change format as needed
Date messageDate = formatter.parse(date);
long since = System.currentTimeMillis() - messageDate.getTime();
long seconds = since/1000;
long minutes = seconds/60;
long hours = minutes/60;
long days = hours/24;
从那里开始,构建你想要的信息对你来说应该是微不足道的。