返回是或否PHP查询

Question

我有以下查询：

    $result = query("SELECT IdUser, followingID FROM following WHERE IdUser = '%d' AND followingID = '%d'", $id, $followingID);

我想知道如果结果是YES，我将如何返回，如果关系存在，我将如何根据0和1计数返回？

Answer 1

这是一种方式：

select (case when exists (SELECT IdUser, followingID
                          FROM following
                          WHERE IdUser = '%d' AND followingID = '%d'
                         )
             then 'YES' else 'NO'
         end) as YesOrNo
, $id, $followingID