Question

我正在尝试导出我的Kunena论坛帖子，将它们导入我们新的wp论坛服务器。为此，我创建了2个文件...一个包含以下格式的消息：

(`id`, `parent`, `thread`, `catid`, `name`, `userid`, `email`, `subject`, `time`, `ip`, `topic_emoticon`, `locked`, `hold`, `ordering`, `hits`, `moved`, `modified_by`, `modified_time`, `modified_reason`)

另一个包含消息的文本：

(`mesid`, `message`)

从第一个文件中我只需要“fields”id，parent，time，userid，subject和hits。从第二个我需要相应的“字段”消息

之后它的格式应该是这样的：

(`id`, `message`, `parent`, `time`, `userid`, `subject`, `hits`)

由于有数百个帖子和副本＆amp;粘贴的东西真的很耗时我认为通过脚本执行此操作要容易得多...最好是通过PowerShell ...

希望你们能帮助我......

$outputFile = "C:\logFile.txt"
$path = "C:\kunena_messages.txt"
$path2 = "C:\kunena_messages_text.txt"

get-content $path | % {$array = $_ -split ",","0"                 
                     $message = get-content $path2 | %{If($_ -match ($array[0].Trim() -replace "\(","" )){
                                $msgArray = $_ -split ",","0"
                                $msgArray[1] -replace "\)",""}}
                      $newString = $array[0].Trim()+","+$message +","+$array[1].Trim()+","+`
                                        $array[8].Trim()+","+$array[5].Trim()+","+$array[7].Trim()+","+`
                                        $array[14].Trim()+")" 
                      $newString | ac $outputFile

}

Answer 1

您可以尝试这样的方法来获取所需的信息：

$outputFile = "C:\logFile.txt"
$path = "C:\test\test.txt"
get-content $path | %{$array = $_ -split ",","0"
                      $message ="This is a message"
                      $newString = "("+$array[0].Trim()+","+$message +","+$array[1].Trim()+","+`
                                        $array[8].Trim()+","+$array[5].Trim()+","+$array[7].Trim()+","+`
                                        $array[14].Trim()+")" 
                      $newString | ac $outputFile
                    }

这将在给定文件（$outputFile）中提供以下输出。

("`id`,`This is a message`,`parent`,`time`,`userid`,`subject`,`hits`)
("`id2`,`This is a message`,`parent2`,`time`,`userid`,`subject`,`hits`)
("`id3`,`This is a message`,`parent2`,`time`,`userid`,`subject`,`hits`)

正如你所看到的，我已经从信息中挑选出你需要的所有部分;因为我不确定你是如何将这两者联系起来的。您需要做的就是使用类似的方法来获取正确的消息并将其放入变量$message。

假设您的ID和MesID相同，您可以对$message变量使用类似的内容：

$path2 = "C:\Messages\test.txt"          
$message = get-content $path2 | %{ $msgArray = $_ -split ",","0" -replace "\)",""
                                   $msgArray = $msgArray -replace "\(",""
                                   $m = $array[0].Trim() -replace "`"","" 
                                   If($msgArray[0].Trim() -eq $m){$msgArray[1]}
                                  }

$path2是您的消息文件的路径。

所以它们应该是这样的：

$outputFile = "C:\logFile.txt"
$path = "C:\kunena_messages.txt"
$path2 = "C:\kunena_messages_text.txt"

get-content $path | %{$array = $_ -split ",","0"
                      $array = $array -replace "\(","" `
                                      -replace "\)","" `
                                      -replace "`"",""
                      $message = get-content $path2 | %{ $msgArray = $_ -split ",","0" -replace "\)",""
                                                         $msgArray = $msgArray -replace "\(",""
                                                         $m = $array[0].Trim() -replace "`"","" 
                                                         If($msgArray[0].Trim() -eq $m){$msgArray[1]}
                                                        }
                      $newString = "("+$array[0].Trim()+","+$message +","+$array[1].Trim()+","+`
                                        $array[8].Trim()+","+$array[5].Trim()+","+$array[7].Trim()+","+`
                                        $array[14].Trim()+")" 
                      $newString | ac $outputFile
                    }

从2个txt文件创建导入文件

1 个答案: