scala中是否有语法或方法来访问case语句中的整个匹配结构?
澄清一下,如果有“as”关键字,可以这样做:
x match {
case Y(z) as matched =>
// do stuff both with "matched" and "z" here ...
...
}
答案 0 :(得分:7)
您应该能够使用@
语法:
x match {
case matched @ Y(z) =>
// do stuff both with "matched" and "z" here ...
...
}
来自here