Question

请查看以下代码：

  def receive: Receive = {
    case Begin(msg, expectedReply, signalSuccessWith, replyTo, receiver, pause) => {
      receiver ! msg
      val cancelHandle = context.system.scheduler.schedule(pause, pause, context.self, Retry)
      context.become(runtime(Begin(msg, expectedReply, signalSuccessWith, replyTo, receiver, pause), cancelHandle))
    }
    case _ =>
  }

我可以看到，当我调用Begin时，我必须完全复制案例类context.become的值，即传递其全部参数。这可行，但看起来像我的代码重复。有没有办法以某种方式按原样获取匹配的值并传递它？

Answer 1

就像那样：

def receive: Receive = {
  case fullMsg @ Begin(msg, expectedReply, signalSuccessWith, replyTo, receiver, pause) => {
    receiver ! msg
    val cancelHandle = context.system.scheduler.schedule(pause, pause, context.self, Retry)
    context.become(runtime(fullMsg, cancelHandle))
  }
  case _ =>
}

如何在匹配模式中获取case类的匹配实例

1 个答案: