Question

嗨我在同一页面上有两个弹出指令。问题是，当我点击它们时，它们都会弹出。

如何将每个范围彼此隔离，以便只弹出点击的弹出窗口？

HTML

<popup class="popup">
  <trigger>
    <a href="#" data-ng-click="showPopup()">Show Popup</a>
  </trigger>
  <pop>
   I popped up
  </pop>
</popup>

<popup class="popup">
  <trigger>
    <a href="#" data-ng-click="showPopup()">Show Popup</a>
  </trigger>
  <pop>
   I popped up too
  </pop>
</popup>

popup.js

angular.module('sembaApp')
  .directive('popup', function () {
    return {
        restrict:  'E',
        replace:    true,
      transclude: true,
      template:   '<div data-ng-transclude></div>',
      controller: function postLink($scope, $element, $attrs) {
        $scope.popup = false;
        $scope.showPopup = function() {
          $scope.popup = !$scope.popup;
        }
      }
    }
  })
  .directive('trigger', function () {
    return {
        require: '^popup',
        restrict:  'E',
        replace:    true,
      transclude: true,
      template:   '<div data-ng-transclude></div>',
    }
  })
  .directive('pop', function () {
    return {
        require: '^popup',
        restrict:  'E',
        replace:    true,
      transclude: true,
      template:   '<aside data-ng-transclude data-ng-show="popup"> yay</aside>'      
    }
  });

Answer 1

为了确保您的每个指令作为不同的范围，您可以向指令函数返回的对象添加scope : true。

你一定要查看documentation（“写指令（长版本）”），它解释了scope属性的强大功能，如何隔离作用域，绑定参数等等......

这stackoverflow question提供了更好的解释。

Answer 2

简化指令可能是一个更好的主意，因此范围很容易处理。

<div ng-app="sembaApp" ng-init="popup1=false;popup2=false;">
    <popup class="popup" ng-model="popup1">
        <pop data-ng-show="popup1">I popped up</pop>
    </popup>
    <popup class="popup" ng-model="popup2">
        <pop data-ng-show="popup2">I popped up too</pop>
    </popup>
</div>

angular.module('sembaApp', [])
    .directive('popup', function () {
    return {
        scope:{
            ngModel: '='
        },
        restrict: 'E',
        replace: true,
        transclude: true,
        template: '<div data-ng-transclude><a href="#" data-ng-click="showPopup()">Show Popup</a></div>',
        link: function postLink($scope, $element, $attrs) {
            $scope.showPopup = function () {
                console.log($scope.ngModel);
                $scope.ngModel = !$scope.ngModel;
            }
        }
    }
})

的 Demo on jsFiddle

Answer 3

通过将$ scope.popup更改为this.popup

来实现它

  <popup class="popup"> 
    <a href="#" data-ng-click="showPopup()">Show Popup</a>
    <pop> 
      I popped up
    </pop>
  </popup>

  controller: function postLink($scope, $element, $attrs) {
    this.popup = false;
    $scope.showPopup = function() {
      this.popup = !this.popup;
    }
  }

具有不同范围的多个AngularJS指令

3 个答案: