如何在python中打印简单操作的完整浮点结果?我的代码确实:
if( int(array_Y[counter2]) == int(round(float(elem[0])))):
if(int(round(float(elem[0]))) == 0):
negatiu_verdader += 1
if(int(round(float(elem[0]))) == 1):
positiu_verdader += 1
counter = counter + 1
counter2 = counter2 + 1
error = float(1.0000- (1.0000 * counter / counter2))
print " ERROR!!!!!!!!!!!!!!!!!!!!!!!! :" + ("{0:.15f}".format(round(error,2)))
但错误总是:0.420000000000000
或0.230000000000000
,但我希望错误为:0.43233213213232
。
答案 0 :(得分:3)
通过调用round(error, 2)
:
>>> round(0.43233213213232, 2)
0.43
如果要显示更高的精确度,请不要这样做:
>>> format(round(0.43233213213232, 2), '.15f')
'0.430000000000000'
>>> format(0.43233213213232, '.15f')
'0.432332132132320'
你在代码中做了很多冗余的工作,简化了一下:
elem_rounded = int(round(float(elem[0])))
if int(array_Y[counter2]) == elem_rounded:
if not elem_rounded:
negatiu_verdader += 1
elif elem_rounded == 1:
positiu_verdader += 1
counter += 1
counter2 += 1
error = 1.0 - (1.0 * counter / counter2)
print " ERROR!!!!!!!!!!!!!!!!!!!!!!!! :{0:.15f}".format(error)