Question

我从php中检索mysql数据库中的一些数据。我写了以下代码。但 而不是重复相同的代码，有没有其他方法可以做到这一点？因为我需要编写相同的代码超过50次。我也用于循环。但我得到了正确的答案。但由于for循环的答案也重复如下

第1章纲要 - 8
第1章Presantation幻灯片 - 8
第1章活动示例 - 8
自我评估测试1- 0
第1章纲要 - 6
第1章Presantation幻灯片 - 6
第1章活动示例 - 6
自我评估测试1- 0
第1章纲要 - 11
第1章Presantation幻灯片 - 11
第1章活动示例 - 11自我评估测试1- 0
第1章概要 - 0
第1章Presantation Slides- 0
第1章活动示例 - 0
自我评估测试1-49

但正确的输出应为

第1章纲要 - 8
第1章演示幻灯片 - 6
第1章示例活动 - 11
自我评估测试1-49

可能是我错误地使用for循环括号或我的代码有什么问题？ 请帮我。我是php mysql的新手，从互联网课程中学习它。（程序是关于计算学习管理系统课程的访问次数）

<?php 
$con=mysqli_connect("localhost:3306","root","", "moodle");
// Check connection
if (mysqli_connect_errno())
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$chap1outr="resource";
$chap1outr1="quiz";


for ($i=81; $i<=116; $i++)
{
    $result1 = mysqli_query ($con,"SELECT count(*) as counts FROM mdl_log WHERE  userid='2' and module='$chap1outr' AND cmid=$i") or die("Error: ".mysqli_error($con));

    while($row1= mysqli_fetch_array( $result1))
    {
        echo "Chapter 1 Outline". "- " . $row1['counts'];
        echo "<br>";
    }

    $result2 = mysqli_query ($con,"SELECT count(*) as counts1 FROM mdl_log WHERE  userid='2' and module='$chap1outr' AND cmid=$i") or die("Error: ".mysqli_error($con));


    while($row2= mysqli_fetch_array( $result2))

    {
        echo "Chapter 1 Presantation Slides". "- " . $row2['counts1'];
        echo "<br>";
    }

    $result3 = mysqli_query ($con,"SELECT count(*) as counts2 FROM mdl_log WHERE  userid='2' and module='$chap1outr' AND cmid=$i") or die("Error: ".mysqli_error($con));


    while($row3= mysqli_fetch_array( $result3))

    {
        echo "Chapter 1 Example Activity". "- " . $row3['counts2'];
        echo "<br>";
    }

    $result4 = mysqli_query ($con,"SELECT count(*) as counts3 FROM mdl_log WHERE  userid='2' and module='$chap1outr1' AND cmid=$i") or die("Error: ".mysqli_error($con));


    while($row4= mysqli_fetch_array( $result4))

    {
        echo "Self Assessment Test 1". "- " . $row4['counts3'];
        echo "<br>";
    }
}
mysqli_close($con);

Answer 1

<?php 
$con=mysqli_connect("localhost:3306","root","", "moodle");
// Check connection
if (mysqli_connect_errno())
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$chap1outr="resource";
$chap1outr1="quiz";


for ($i=81; $i<=116; $i++)
{
    $result1 = mysqli_query ($con,"SELECT count(*) as counts FROM mdl_log WHERE  userid='2' and module='$chap1outr' AND cmid=$i") or die("Error: ".     mysqli_error($con));

    $row1= mysqli_fetch_array( $result1);
    echo "Chapter 1 Outline". "- " . $row1['counts']."<br>";
    echo "Chapter 1 Presantation Slides". "- " . $row1['counts']."<br>";
    echo "Chapter 1 Example Activity". "- " . $row1['counts']."<br>";
    echo "Self Assessment Test 1". "- " . $row1['counts']."<br>";


}
mysqli_close($con);

如何从php（从for循环）中检索mysql数据库中的数据

1 个答案: