我正在学习休眠,当我运行以下程序时,我收到此消息:
Hibernate: insert into contact (firstname, lastname, email, id) values (?, ?, ?, ?)
但是当我查看表格时,似乎没有插入任何内容。这有什么问题?很明显,语句值字段为空,但为什么呢?
我有以下POJO:
public class Contact {
private String firstName;
private String lastName;
private String email;
private long id;
/**
* @return Email
*/
public String getEmail() {
return email;
}
/**
* @return First Name
*/
public String getFirstName() {
return firstName;
}
/**
* @return Last name
*/
public String getLastName() {
return lastName;
}
/**
* @param string Sets the Email
*/
public void setEmail(String string) {
email = string;
}
/**
* @param string Sets the First Name
*/
public void setFirstName(String string) {
firstName = string;
}
/**
* @param string sets the Last Name
*/
public void setLastName(String string) {
lastName = string;
}
/**
* @return ID Returns ID
*/
public long getId() {
return id;
}
/**
* @param l Sets the ID
*/
public void setId(long l) {
id = l;
}
}
以下是我的hibernate配置和hbm文件:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost/aneesh</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password">123</property>
<property name="hibernate.connection.pool_size">10</property>
<property name="show_sql">true</property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="hibernate.hbm2ddl.auto">update</property>
<!-- Mapping files -->
<mapping resource="contact.hbm.xml"/>
</session-factory>
</hibernate-configuration>
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="Contact" table="contact">
<id name="id" column="id" >
<generator class="assigned"/>
</id>
<property name="firstName" >
<column name="firstname" />
</property>
<property name="lastName">
<column name="lastname"/>
</property>
<property name="email" >
<column name="email"/>
</property>
</class>
</hibernate-mapping>
这是我要插入的代码:
import org.hibernate.HibernateException;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;
import org.hibernate.Session;
public class HSession {
public static void main(String[] args) {
Session session = null;
try{
SessionFactory sessionGet = new Configuration().configure().buildSessionFactory();
session = sessionGet.openSession();
Contact contact = new Contact();
contact.setFirstName("xyz");
contact.setLastName("zyx");
contact.setEmail("x@xmail.com");
contact.setId(20);
session.save(contact);
}finally{
// Actual contact insertion will happen at this step
try {
session.flush();
session.close();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
答案 0 :(得分:2)
在保存对象之前,您必须获得事务,在保存对象后,您必须提交事务。
Transaction tx = session.beginTransaction();
session.save(contact);
tx.commit();
答案 1 :(得分:2)
在保存中使用transaction
。
session.getTransaction().begin();
session.save(contact);
session.getTransaction().commit();
答案 2 :(得分:2)
您忘记了开始并提交了交易。
session = sessionGet.openSession();
**Transaction tx= session.beginTransaction();**
Contact contact = new Contact();
contact.setFirstName("xyz");
contact.setLastName("zyx");
contact.setEmail("x@xmail.com");
contact.setId(20);
session.save(contact);
**tx.commit();**
答案 3 :(得分:1)
您应该提交插件以反映在数据库中 尝试强>
session.getTransaction().commit();
之后
session.save(contact);