我的项目中有这些POJO课程。
public class MerchantChainUser extends com.avanza.ni.common.dto.AbstractDTO
implements java.io.Serializable {
private long chainId;
private CompositePK compositePK;
public MerchantChainUser() {
}
public void setChainId(long chainId) {
this.chainId = chainId;
}
public long getChainId() {
return chainId;
}
public void setCompositePK(CompositePK compositePK) {
this.compositePK = compositePK;
}
public CompositePK getCompositePK() {
return compositePK;
}
}
AND
public class CompositePK implements Serializable {
private long merchantId;
private long userId;
public void setMerchantId(long merchantId) {
this.merchantId = merchantId;
}
public long getMerchantId() {
return merchantId;
}
public void setUserId(long userId) {
this.userId = userId;
}
public long getUserId() {
return userId;
}
}
MerchantUserChain
的hbm.xml文件是
<hibernate-mapping>
<class name="com.avanza.ni.portal.dto.MerchantChainUser" table="MERCHANT_CHAIN_USER">
<composite-id name="compositePK">
<key-property name="merchantId" type="long" column="MERCHANT_ID"></key-property>
<key-property name="userId" type="long" column="MERCHANT_USER_ID"></key-property>
</composite-id>
<property name="chainId" type="long">
<column name="MERCHANT_CHAIN_ID" length="38" />
</property>
</class>
现在我想要的是我必须使用MERCHANT_USER_ID
从表中读取数据。我能够从表中检索整个数据,但现在我想将标准设置为Only give me those row that MERCHANT_USER_ID is specific
。我不知道如何编写数据标准。
答案 0 :(得分:2)
我把评论的答案删除了,所以我在这里发布:D
Criteria crit = session.createCriteria(MerchantChainUser.class)
.add(Restrictions.eq("compositePK.userId", userId));
或使用hql
session.createQuery("from MerchantChainUser where compositePK.userId = :userid").setParameter("userid",userid);
答案 1 :(得分:0)
你可以尝试:
Criteria crit = session.createCriteria(MerchantChainUser.class);
crit.add(Restrictions.eq("compositePK.merchantId", 42));
crit.add(Restrictions.eq("compositePK.userId", 43));
crit.setMaxResults(10);
List result = crit.list();
摄影指导Vinit