我在hibernate中有以下实体,使用JPA注释
@Entity
@IdClass(PurchaseCounter.PurchaseCounterPK.class)
@Table(name = "customer_purchases_counter")
public class PurchaseCounter {
public static class PurchaseCounterPK implements Serializable {
Integer customerId;
Integer purchaseId;
public PurchaseCounterPK(Integer customerId, Integer purchaseId) {
this.customerId = customerId;
this.purchaseId = purchaseId;
}
public Integer getCustomerId() {
return customerId;
}
public void setCustomerId(Integer customerId) {
this.customerId = customerId;
}
public Integer getPurchaseId() {
return purchaseId;
}
public void setPurchaseId(Integer purchaseId) {
this.purchaseId = purchaseId;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
PurchaseCounterPK that = (PurchaseCounterPK) o;
if (customerId != null ? !customerId.equals(that.customerId) : that.customerId != null) return false;
if (purchaseId != null ? !purchaseId.equals(that.purchaseId) : that.purchaseId != null) return false;
return true;
}
@Override
public int hashCode() {
int result = customerId != null ? customerId.hashCode() : 0;
result = 31 * result + (purchaseId != null ? purchaseId.hashCode() : 0);
return result;
}
}
Integer customerId;
Integer purchaseId;
Integer count = 0;
@Id
@Column(name = "customer_id")
public Integer getCustomerId() {
return customerId;
}
public void setCustomerId(Integer customerId) {
this.customerId = customerId;
}
@Id
@Column(name = "purchase_id")
public Integer getPurchaseId() {
return purchaseId;
}
public void setPurchaseId(Integer purchaseId) {
this.purchaseId = purchaseId;
}
public Integer getCount() {
return count;
}
public void setCount(Integer count) {
this.count = count;
}
}
当我使用Criteria进行查询并使用purchaseId和customerId作为Restriction.eq过滤器时,这就是生成的查询:
select this_.customerId as customerId137_0_, this_.purchaseId as purchaseId137_0_, this_.count as count137_0_ from customer_purchases_counter this_ where this_.purchaseId=? and this_.customerId=?
当然是错误的,因为字段customerId和purchaseId没有重命名为我使用@Column指定的名称????
答案 0 :(得分:1)
映射似乎是正确的。这可能是HHH-4256的发生( Hibernate不使用IdClass 来表示@Column(name = ...)注释)。如果是这样,那么更新到更新版本的Hibernate会提供解决方案。
另外,根据@Column
中使用IdClass
注释的错误报告是解决方法。
答案 1 :(得分:-1)
我不确定我是否理解正确,但@Column只指定要映射到java数据的列。
所以你不应该将@Column注释应用于你的getter,而应该应用于你的变量声明。
@ID
@Column (name="customer_Id")
Integer customerId;
@ID
@Column (name="purchase_Id")
Integer purchaseId;