我正在尝试使用复合主键在学生和教学课程之间创建多种语言:
我的班级:
@Entity
@Table(name="Student_mtm_cId")
public class Student {
private String id;
private Set<StudentTClass> teachingClasses = new HashSet<StudentTClass>();
@OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.student")
public Set<StudentTClass> getTeachingClasses() {
return teachingClasses;
}
public void setTeachingClasses(Set<StudentTClass> teachingClasses) {
this.teachingClasses = teachingClasses;
}
public void addStudentToClass(TeachingClass teachingClass){
StudentTClass studentTClass = new StudentTClass();
studentTClass.setStudent(this);
studentTClass.setTeachingClass(teachingClass);
teachingClasses.add(studentTClass);
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
@Id @GeneratedValue(generator="system-uuid")
@GenericGenerator(name="system-uuid", strategy = "uuid")
@Column(name = "student_id", nullable = false)
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
//all other setters and getters and isequal/hashCode omitted.
}
TeachingClass:
@Entity
@Table(name="TechingClass_MTM")
public class TeachingClass {
private String id;
private String name;
private String description;
private Set<StudentTClass> teachingClasses = new HashSet<StudentTClass>();
public TeachingClass(){}
public TeachingClass(String name, String description) {
super();
this.name = name;
this.description = description;
}
public void addStudentToClass(Student student){
StudentTClass studentTClass = new StudentTClass();
studentTClass.setStudent(student);
studentTClass.setTeachingClass(this);
teachingClasses.add(studentTClass);
}
@OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.teachingClass")
public Set<StudentTClass> getTeachingClasses() {
return teachingClasses;
}
public void setTeachingClasses(Set<StudentTClass> teachingClasses) {
this.teachingClasses = teachingClasses;
}
public void setDescription(String description) {
this.description = description;
}
@Id @GeneratedValue(generator="system-uuid")
@GenericGenerator(name="system-uuid", strategy = "uuid")
@Column(name = "teachingClass_id", nullable = false)
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
}
收集对象:
@Entity
@Table(name = "student_TClass_MTM")
@AssociationOverrides({
@AssociationOverride(name = "pk.student", joinColumns = @JoinColumn(name = "student_id")),
@AssociationOverride(name = "pk.teachingClass", joinColumns = @JoinColumn(name = "teachingClass_id"))
})
public class StudentTClass {
@EmbeddedId
private StudentTClassPK pk = new StudentTClassPK();
public StudentTClassPK getPk() {
return pk;
}
public void setPk(StudentTClassPK pk) {
this.pk = pk;
}
public StudentTClass() {}
@Transient
public Student getStudent(){
return this.pk.getStudent();
}
@Transient
public TeachingClass getTeachingClass(){
return this.pk.getTeachingClass();
}
public void setStudent(Student student){
this.pk.setStudent(student);
}
public void setTeachingClass(TeachingClass teachingClass){
this.pk.setTeachingClass(teachingClass);
}
}
现在主键:
@Embeddable
public class StudentTClassPK implements Serializable{
private static final long serialVersionUID = -7261887879839337877L;
private Student student;
private TeachingClass teachingClass;
@ManyToOne
public Student getStudent() {
return student;
}
public void setStudent(Student student) {
this.student = student;
}
@ManyToOne
public TeachingClass getTeachingClass() {
return teachingClass;
}
public void setTeachingClass(TeachingClass teachingClass) {
this.teachingClass = teachingClass;
}
public StudentTClassPK(Student student, TeachingClass teachingClass) {
this.student = student;
this.teachingClass = teachingClass;
}
public StudentTClassPK() {}
}
当我试图坚持学生时,我收到以下错误:
Caused by: org.hibernate.MappingException: Could not determine type for: com.vanilla.objects.Student, at table: student_TClass_MTM, for columns: [org.hibernate.mapping.Column(student)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:306)
at org.hibernate.tuple.PropertyFactory.buildStandardProperty(PropertyFactory.java:143)
at org.hibernate.tuple.component.ComponentMetamodel.<init>(ComponentMetamodel.java:68)
at org.hibernate.mapping.Component.buildType(Component.java:184)
at org.hibernate.mapping.Component.getType(Component.java:177)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:290)
at org.hibernate.mapping.RootClass.validate(RootClass.java:236)
at org.hibernate.cfg.Configuration.validate(Configuration.java:1362)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1865)
at org.springframework.orm.hibernate3.LocalSessionFactoryBean.newSessionFactory(LocalSessionFactoryBean.java:855)
at org.springframework.orm.hibernate3.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:774)
at org.springframework.orm.hibernate3.AbstractSessionFactoryBean.afterPropertiesSet(AbstractSessionFactoryBean.java:211)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1477)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1417)
... 51 more
我做错了什么?
答案 0 :(得分:13)
我解决了这个问题。我映射了Getter而不是字段。
public class StudentTClass {
//@EmbeddedId
private StudentTClassPK pk = new StudentTClassPK();
@EmbeddedId
public StudentTClassPK getPk() {
return pk;
}
答案 1 :(得分:5)
如果可以的话,我会认真建议删除复合键。值得使用简单的主键可以解决许多问题并简化代码。我过去在数据库中使用过复合键,因为我无法修改数据库。不幸的是我没有代码。但我确实记得需要一些工作才能让它正常工作。对不起,不禁多了。