Question

假设我在Mongo中有以下数据：

{
    "id": "foo1",
    "description": "myFoo1",
    "bars": [
        {
            "id": "foo1bar1",
            "description": "myFoo1Bar1",
            "builton": "2010-03-01T05:00:00.000Z"
        },
        {
            "id": "foo1bar2",
            "description": "myFoo1Bar2",
            "builton": "2011-03-01T05:00:00.000Z"
        }
    ]
}
{
    "id": "foo2",
    "description": "myFoo2",
    "bars": [
        {
            "id": "foo2bar1",
            "description": "myFoo2Bar1",
            "builton": "2012-03-01T05:00:00.000Z"
        },
        {
            "id": "foo2bar2",
            "description": "myFoo2Bar2",
            "builton": "2013-03-01T05:00:00.000Z"
        }
    ]
}

我的问题是双重的，我想：

是否可以执行一个查询，该查询只会返回日期介于指定范围内的bar的文档，并且只返回该日期范围内的bars？例如，如果我的日期范围是2010-02-01到2010-04-01，那么这就是我想要的回复：

{
    "id": "foo1",
    "description": "myFoo1",
    "bars": [
        {
            "id": "foo1bar1",
            "description": "myFoo1Bar1",
            "builton": "2010-03-01T05:00:00.000Z"
        }
    ]
}

这是构建数据的最佳方式吗？还是我应该更加关联（即有两个单独的文档（foos和bars）然后只有一个fooId字段bar）？

Answer 1

通常，您将始终获得完整的文档。如果你真的只想要一个子数组的一个元素，那么你最好的选择是将每个“bar”分成它自己的文档。在这种情况下，使用两个集合可能会更好，就像你在RDBM中那样，但也可以只存储这样的东西：

{
    "foo" : {
        "id": "foo1",
        "description": "myFoo1",
    }
    "id": "foo1bar1",
    "description": "myFoo1Bar1",
    "builton": "2010-03-01T05:00:00.000Z"
},
{
    "foo" : {
        "id": "foo1",
        "description": "myFoo1",
    }
    "id": "foo1bar2",
    "description": "myFoo1Bar2",
    "builton": "2011-03-01T05:00:00.000Z"
}

即，在每个栏中存储“foo”信息。

查询以过滤数组值属性

1 个答案: