如何在PHP中过滤此数组,使其仅包含[is_published] = 1
?
我整个下午一直在寻找Stack Overflow并试过filter_array
和其他方法,但我无法做到正确......
FB_manager_array2: Array
(
[0] => Array
(
[data] => Array
(
[0] => Array
(
[id] => 244987165675334
[is_published] => 1
[name] => Zitecraft.com
)
[1] => Array
(
[id] => 437060646380356
[is_published] => 1
[name] => Beauty & care Alexandra
)
[2] => Array
(
[id] => 663302210366640
[is_published] => 1
[name] => Tiramisu Gelato ijssalon
)
[3] => Array
(
[id] => 295426223953905
[is_published] => 1
[name] => Ck's Hairstyling
)
[4] => Array
(
[id] => 213820525062
[is_published] => 1
[name] => Citynumbers.com - Feel like going out tonight?
)
[5] => Array
(
[id] => 114373308748798
[is_published] => 1
[name] => YOLO: You Only Live Once
)
[6] => Array
(
[id] => 200408800066160
[is_published] =>
[name] => Citynumbers Social Widget
)
)
[paging] => Array
(
[cursors] => Array
(
[before] => MjQ0OTg3MTY1Njc1MzM0
[after] => MjAwNDA4ODAwMDY2MTYw
)
)
)
)
答案 0 :(得分:1)
使用array_filter:
$FB_manager_array2[0]['data'] = array_filter($FB_manager_array2[0]['data'], function($v) {
return $v['is_published'] == '1';
});