Question

我有登录页面和登录操作。当用户登录操作返回“成功”结果时。它必须去另一个行动。但是我收到以下错误：

HTTP状态404 - / ESA / protected / admin / list
description请求的资源不可用。

这是我的struts.xml文件：

    <action name="login" class="ir.imrasta.esa.ui.action.UserAction" method="login">
        <result name="success">protected/admin/list</result>
        <result name="failed">/login.jsp?login=failed</result>
    </action>

    <action name="/protected/admin/list" class="ir.imrasta.esa.ui.action.ManagerAction" method="list">
        <result name="success">/protected/admin/list.jsp</result>
    </action>

在上面的代码中查看<result name="success">/protected/admin/list</result>。如果我用jsp页面更改它可以正常工作。

更新2013/07/20：

web.xml：

<?xml version="1.0" encoding="UTF-8"?>  
<web-app id="WebApp_9" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<display-name>Educational System Application</display-name>

<filter>
    <filter-name>loginFilter</filter-name>
    <filter-class>ir.imrasta.esa.ui.filter.LoginFilter</filter-class>
</filter>
<filter-mapping>
    <filter-name>loginFilter</filter-name>
    <url-pattern>/protected/*</url-pattern>
</filter-mapping>

<filter>
    <filter-name>struts2</filter-name>
    <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
    <filter-name>struts2</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<welcome-file-list>
    <welcome-file>index.html</welcome-file>
</welcome-file-list>

struts.xml：

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd">
<struts>

<constant name="struts.devMode" value="true" />
<constant name="struts.custom.i18n.resources" value="languages" />

<package name="default" namespace="/" extends="struts-default">

    <default-action-ref name="index" />

    <global-results>
        <result name="error">/error.jsp</result>
    </global-results>

    <global-exception-mappings>
        <exception-mapping result="error" exception="java.lang.Exception"/>
        <exception-mapping result="error" exception="ir.imrasta.esa.bll.exceptions.DataSourceException"/>
        <exception-mapping result="error" exception="ir.imrasta.esa.bll.exceptions.DecryptionException"/>
    </global-exception-mappings>

    <action name="index">
        <result>/index.jsp</result>
    </action>

    <action name="login" class="ir.imrasta.esa.ui.action.UserAction" method="login">
        <result name="success">protected/admin/list</result>
        <result name="failed">/login.jsp?login=failed</result>
    </action>

    <action name="/protected/admin/list" class="ir.imrasta.esa.ui.action.ManagerAction" method="list">
        <result name="success">/protected/admin/home.jsp</result>
    </action>

</package>

<!-- Add packages here -->

</struts>

loginFilter：

public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException{
    HttpServletRequest req=(HttpServletRequest) request;
    HttpSession session=req.getSession();
    User user=(User)session.getAttribute(Constants.SESSION_USER);
    if (user!=null){
        chain.doFilter(request, response);
    }else{
        RequestDispatcher dispatcher=req.getRequestDispatcher("/login.jsp");
        dispatcher.forward(request, response);
    }
}

Answer 1

甚至看到你所引用的动作类也需要在struts.xml中映射，你获得404的原因是你找到的动作类没有在struts中找到任何映射

Answer 2

要重定向到其他操作，您需要使用redirectAction结果类型。

<action name="login" class="ir.imrasta.esa.ui.action.UserAction" method="login">
    <result name="success" type="redirectAction">protected/admin/list</result>
    <result name="failed">/login.jsp?login=failed</result>
</action>

默认情况下，不允许使用动作名称中的斜杠。要在动作名称中允许斜杠，您需要在struts.enable.SlashesInActionNames文件中将struts.xml常量设置为true。

<constant name="struts.enable.SlashesInActionNames" value="true" />

struts2结果请求的资源不可用

2 个答案: