Question

SQL Server 2005

我正在尝试将结果集压缩为每个人员有一行数据，我的查询是

SELECT  Staff +'- '+ CONVERT(CHAR(2),Service_Date, 110) AS Staff
,(SELECT COUNT (Procedure_) WHERE Procedure_ Like '90791%' ) AS '90791' 
,(SELECT COUNT (Procedure_) WHERE Procedure_ Like'90832%' )  AS '90832'
,(SELECT COUNT (Procedure_) WHERE Procedure_ Like'90834%' )  AS  '90834'
,(SELECT COUNT (Procedure_) WHERE Procedure_ Like'90837%' )  AS '90837' 
,(SELECT COUNT (Procedure_) WHERE Procedure_ Like '90847%')  AS '90847'

FROM dbo.Service_History 
WHERE Program='OPCC'
AND STATUS='Kept'
AND TYPE = 'Client'
AND Procedure_ IS NOT NULL 
AND Service_date BETWEEN DATEADD(mm, DATEDIFF(mm, 0,GETDATE())-3, 0)  AND  GETDATE()


GROUP BY Staff +'- '+ CONVERT(CHAR(2),Service_Date, 110),Procedure_ 
ORDER BY Staff +'- '+ CONVERT(CHAR(2),Service_Date, 110),Procedure_

GROUP BY Staff +'- '+ CONVERT(CHAR(2),Service_Date, 110),Procedure_ 
ORDER BY Staff +'- '+ CONVERT(CHAR(2),Service_Date, 110),Procedure_

结果集如下:(每个人员一行，返回一列数据，另一行为NULL行）。

Staff                       90791   90832   90834   90837   90847
Smith, Joe (568)- 04    15  NULL    NULL    NULL    NULL
Smith, Joe (568)- 04    NULL    NULL    2   NULL    NULL
Smith, Joe (568)- 04    NULL    NULL    NULL    1   NULL
Smith, Joe (568)- 04    NULL    NULL    NULL    NULL    NULL

我想将上述结果归结为一行。基本上每个工作人员每月一行，总计执行的程序数。

喜欢这些：

Staff                       90791   90832   90834   90837   90847
Smith, Joe (568)- 04    15  NULL    2   1   NULL

我可以通过将结果导入临时表然后查询临时表来获得结果来实现我想要的结果，但这远非有效，我希望有更好的解决方案。

Answer 1

您可以获取每个字段的MAX（）。即：

ID  a     b     c     d
1   1     NULL  NULL  NULL
1   NULL  1     NULL  NULL
1   NULL  NULL  1     NULL

SELECT ID
     , MAX(a) AS a
     , MAX(b) AS b
     , MAX(c) AS c
     , MAX(d) as d
FROM Table
GROUP BY ID

结果：

ID  a   b   c    d
1   1   1   1    NULL

Answer 2

做这样的事情：

select staff + convert(char(2),service_date,110) staff,
count(case when procedure like '90791%' then staff end) '90791',
count(case when procedure like '90832%' then staff end) '90832',
count(case when procedure like '90834%' then staff end) '90834',
count(case when procedure like '90837%' then staff end) '90837',
count(case when procedure like '90847%' then staff end) '90847'

from service_history
where program='OPCC'
 ....
group by staff + convert(char(2),service_date,110)

应该这样做！

SQL Server 2005将结果集压缩为一行返回值

2 个答案: