Question

我写了这样的SQL查询。

SELECT
    TR.TRAN_DATE,
    CASE WHEN tr.CR_DR='CR' THEN sum(TR.GL_TRN_AMT) ELSE 0 END AS CR,
    CASE WHEN tr.CR_DR='DR' THEN sum(TR.GL_TRN_AMT) ELSE 0 END AS DR
FROM 
    [COREBANKER1].[dbo].[GL_DAILY_TRN] AS TR 
WHERE 
    TR.GL_CODE = '01010101' 
    AND TR.BRANCH_CODE = 1000 
    AND TR.TRAN_DATE BETWEEN '2016-11-01' AND '2017-03-01' 
GROUP BY
    TR.TRAN_DATE, TR.CR_DR, TR.[BRANCH_CODE] 
ORDER BY 
    TR.TRAN_DATE

结果如下：

Result

但我想将DR CR结果放在一行。

Answer 1

进行条件聚合时，case是sum()：

的参数

SELECT TR.TRAN_DATE,
       SUM(CASE WHEN tr.CR_DR = 'CR' THEN TR.GL_TRN_AMT ELSE 0
           END) AS CR,
       SUM(CASE WHEN tr.CR_DR='DR' THEN TR.GL_TRN_AMT ELSE 0
           END) AS DR
FROM [COREBANKER1].[dbo].[GL_DAILY_TRN] TR
WHERE TR.GL_CODE = '01010101' AND
      TR.BRANCH_CODE=1000 AND
      TR.TRAN_DATE BETWEEN '2016-11-01' AND '2017-03-01' 
GROUP BY TR.TRAN_DATE --, TR.[BRANCH_CODE] 
ORDER BY TR.TRAN_DATE;

我不知道你是否想为每个分支分别设置一行。如果您这样做，请取消注释GROUP BY中的引用。

SQL结果合并为一行

1 个答案: