我正在尝试打印从图像文件中输入的矩阵的值,该文件的类型为CV_8UC4。我的代码写在下面。我的问题是我得到的值只有48和255,而我期待的值是2和1或者其他什么。有人知道为什么吗?我想我是以错误的方式打印价值观。有没有其他方法来打印CV_8UC4的值。 我的代码是:
CvMat* m1 = cvLoadImageM(argv[1], CV_LOAD_IMAGE_UNCHANGED); // load the matrix from an image file
cv::Mat m1cpp(m1);
int type = m1cpp.type();
printf( " type is %d ", type );
switch( type ) {
case 24:
printf("\n --> Matrix type is CV_8U \n");
for( size_t i = 0; i < m1cpp.rows; i++ ) {
for( size_t j = 0; j < m1cpp.cols; j++ ) {
printf( " %d ", m1cpp.at<uchar>(i,j) );
} printf("\n");
}
break;
case 25:
printf("\n --> Matrix type is CV_8S \n");
for( size_t i = 0; i < m1cpp.rows; i++ ) {
for( size_t j = 0; j < m1cpp.cols; j++ ) {
printf( " %d ", m1cpp.at<schar>(i,j) );
} printf("\n");
}
break;
case 18:
printf("\n --> Matrix type is CV_16U \n");
for( size_t i = 0; i < m1cpp.rows; i++ ) {
for( size_t j = 0; j < m1cpp.cols; j++ ) {
printf( " %d ", m1cpp.at<ushort>(i,j) );
} printf("\n");
}
break;
case 27:
printf("\n --> Matrix type is CV_16S \n");
for( size_t i = 0; i < m1cpp.rows; i++ ) {
for( size_t j = 0; j < m1cpp.cols; j++ ) {
printf( " %d ", m1cpp.at<short>(i,j) );
} printf("\n");
}
break;
case 28:
printf("\n --> Matrix type is CV_32S \n");
for( size_t i = 0; i < m1cpp.rows; i++ ) {
for( size_t j = 0; j < m1cpp.cols; j++ ) {
printf( " %d ", m1cpp.at<int>(i,j) );
} printf("\n");
}
break;
case 29:
printf("\n --> Matrix type is CV_32F \n");
for( size_t i = 0; i < m1cpp.rows; i++ ) {
for( size_t j = 0; j < m1cpp.cols; j++ ) {
printf( " %.3f ", m1cpp.at<float>(i,j) );
} printf("\n");
}
break;
case 30:
printf("\n --> Matrix type is CV_64F \n");
for( size_t i = 0; i < m1cpp.rows; i++ ) {
for( size_t j = 0; j < m1cpp.cols; j++ ) {
printf( " %.3f ", m1cpp.at<double>(i,j) );
} printf("\n");
}
break;
default:
printf("\n --> Matrix type not found \n");
}
我的情况是24,我的有线值为48和255.还有其他方法可以打印CV_8UC4值吗?
答案 0 :(得分:5)
正确访问您的CV_8UC4
矩阵:
image.at<cv::Vec4b>(j,i)[0];
image.at<cv::Vec4b>(j,i)[1];
image.at<cv::Vec4b>(j,i)[2];
image.at<cv::Vec4b>(j,i)[3];