我有以下表格列值:
2013-06-28T13:00:00.000Z Motion
2013-06-28T18:15:00.000Z Static (row2)
2013-07-03T13:57:22.000Z Moving (row3)
2013-07-03T13:59:00.000Z Motion
我想检查日期29-06-2013T01:00:00Z
和29-06-2013T05:00:00Z
是否都是静态。同样,我想查看日期30-06-2013T01:00:00Z
和30-06-2013T05:00:00Z
。
显然,如果我们考虑上面的表值,则这是正确的,因为两个日期都在第2行和第3行之间。
如何使用sqlite做到这一点?
我收到的日期为29-06-2013
和30-06-2013
。首先,我需要将这些日期的凌晨1点和5点设置为两个日期,然后检查它们是否都是静态。
我尝试了以下内容:
Calendar cal1 = Calendar.getInstance();
cal1.setTime(input1.parse(startDate.get(0))); //29-06-2013
cal1.add(Calendar.AM, 1); //Added 1am to date 29-06-2013
weekHours = cal1.getTime();
Cursor chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
+ input1.format(weekHours) + "' order by Date asc LIMIT 1", null);
chkCur1.moveToFirst();
if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static"))
{
cal1.add(Calendar.AM, 5); //Added 5am to date 29-06-2013
weekHours = cal1.getTime();
}
chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
+ input1.format(weekHours) + "' order by Date asc LIMIT 1", null);
chkCur1.moveToFirst();
if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static")){
cal1.add(Calendar.DATE, 1);
cal1.add(Calendar.AM, 1); //Added 1am to date 30-06-2013
weekHours = cal1.getTime();
}
chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
+ input1.format(weekHours) + "' order by Date asc LIMIT 1", null);
chkCur1.moveToFirst();
if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static")){
cal1.add(Calendar.AM, 5); //Added 5am to date 30-06-2013
weekHours = cal1.getTime();
}
chkCur1 = dbAdapter.rawQuery("select movement from user where Date <= '"
+ input1.format(weekHours) + "' order by Date asc LIMIT 1", null);
chkCur1.moveToFirst();
if(!chkCur1.isAfterLast() && chkCur1.getString(0).equals("Static")){
System.out.println("Both dates are in between")
}
我使用了4个SQL查询:
1)将时间1am
设置为date1并检查其上一个是否为静态。
2)将时间5am
设置为date1并检查其上一个是否为静态。
3)将时间1am
设置为date2并检查其上一个是否为静态。
4)将时间5am
设置为date2并检查其上一个是否为静态。
如果所有条件都满足,则两个日期(date1和date2)介于两者之间,即静态。
但这是sql查询的重复,从而减慢了进程。
答案 0 :(得分:1)
您可以将所有四项检查放入子查询中:
SELECT (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static'
AND (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static'
AND (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static'
AND (SELECT movement FROM user WHERE Date <= ? ORDER BY Date) = 'Static';
这将为您提供一个带有单个布尔列的结果记录。