Question

我有一个表单，用户从日历中获取两个日期。我想检查用户选择的两个日期之间的天数是从星期五到星期一（包括）。

我找到了平日计算的脚本（包括satuday和星期日的日子）：

function calcBusinessDays (dDate1, dDate2) {
    var iWeeks, iDateDiff, iAdjust = 0;

    if (dDate2 < dDate1) return 0;

    var iWeekday1 = dDate1.getDay();
    var iWeekday2 = dDate2.getDay();

    iWeekday1 = (iWeekday1 == 0) ? 7 : iWeekday1; // change Sunday from 0 to 7
    iWeekday2 = (iWeekday2 == 0) ? 7 : iWeekday2;

    if ((iWeekday1 > 5) && (iWeekday2 > 5)) iAdjust = 1; // adjustment if both days on weekend

    iWeekday1 = (iWeekday1 > 5) ? 5 : iWeekday1; // only count weekdays
    iWeekday2 = (iWeekday2 > 5) ? 5 : iWeekday2;

    // calculate differnece in weeks (1000mS * 60sec * 60min * 24hrs * 7 days = 604800000)
    iWeeks = Math.floor((dDate2.getTime() - dDate1.getTime()) / 604800000)

    if (iWeekday1 <= iWeekday2) {
        iDateDiff = (iWeeks * 5) + (iWeekday2 - iWeekday1)
    } else {
        iDateDiff = ((iWeeks + 1) * 5) - (iWeekday1 - iWeekday2)
    }

    iDateDiff -= iAdjust // take into account both days on weekend

    return (iDateDiff + 1); // add 1 because dates are inclusive
}

如何修改它以包括星期五和星期一？

Answer 1

只需快速将它们放在一起，但它应该可行。我无法理解您的示例代码。只是觉得这可能会好一点。

var calcBusinessDays = function (dDate1, dDate2) {
    //We are working with time stamps
    var from = dDate1.getTime()
    ,   to = dDate2.getTime()
    ,   tempDate = new Date()
    ,   count = 0;

    //loop through each day between the dates 86400000 = 1 day
    for(var _from = from; _from < to; _from += 86400000){
        //set the day
        tempDate.setTime(_from);
        //If it is a weekend add 1 to count
        if ((tempDate.getDay() <= 1) || (tempDate.getDay() >= 5)) {
            count++;
        }
    }

    //return count =)
    return count;
}

这将在星期五，星期六，星期日和星期一加1。如果您想要其他日子，唯一需要更改的行是if语句嵌套在for循环中。

如何检查两个日期之间的天数是否为工作日？

1 个答案: