Question

我有一张桌子：

HOST_ID | ContractYear
1       | 2008
2       | 2008
3       | 2008
1       | 2009
4       | 2009

我需要的是一个查询，它会告诉我2009年的所有HOST_ID都不是2008年。

上例中的答案是HOST_ID = 4.

感谢。

Answer 1

select
  HOST_ID
from
  table_name
where
  ContractYear = 2009
  AND HOST_ID NOT IN (select HOST_ID from table_name where ContractYear = 2008)

Answer 2

使用：

SELECT t.host_id
  FROM TABLE t
 WHERE t.contractyear = 2009
   AND NOT EXISTS(SELECT NULL
                    FROM TABLE t2
                   WHERE t2.host_id = t.host_id
                     AND t.contractyear = 2008)

Answer 3

SELECT  DISTINCT host_id
FROM    mytable mo
WHERE   ContractYear = 2009
        AND NOT EXISTS
        (
        SELECT  NULL
        FROM    mytable mi
        WHERE   mi.host_id = mo.host_id
                AND ContractYear = 2008
        )

Answer 4

更通用，因为它会过滤所有不是您正在寻找的年份

select HOST_ID
from table t
where ContractYear = 2009
and HOST_ID not in (select distinct HOST_ID
                    from table t2
                    where t.ContractYear != t2.ContractYear)

MySQL：获取id为一年而不是另一年的所有记录

4 个答案: