尝试运行测试代码时出现以下错误:
thread failed to start: Invalid value for shared scalar at ./threaded_test.pl line 47.
第47行是:
%hoh = hoh(@new_array);
我的观察:
%hoh
的行,则脚本会正常运行%new_hash = (itchy => "Scratchy");
但是当我尝试从另一个子句(第47行)“返回”哈希时,会导致上面的错误。不幸的是,我无法使用输入/输出队列,因为我使用的Thread :: Queue版本太旧(并且安装在我无法控制的系统上)并且不支持散列和散列引用类型通过队列返回(根据this)。显然,我的版本只支持通过队列返回的字符串。
有没有办法成功执行此操作:$hash{$string}{"jc"} = \%hoh;
#!/usr/bin/perl
use strict;
use warnings;
use threads;
use Thread::Queue;
use constant NUM_WORKERS => 10;
my @out_array : shared = ();
main();
sub main
{
my @results = test1();
foreach my $item (@results) {
print "item: $item\n";
}
}
sub test1
{
my $my_queue = Thread::Queue->new();
foreach (1..NUM_WORKERS) {
async {
while (my $job = $my_queue->dequeue()) {
test2($job);
}
};
}
my @sentiments = ("Axe Murderer", "Mauler", "Babyface", "Dragon");
$my_queue->enqueue(@sentiments);
$my_queue->enqueue(undef) for 1..NUM_WORKERS;
$_->join() for threads->list();
my @return_array = @out_array;
return @return_array;
}
sub test2
{
my $string = $_[0];
my %hash : shared;
my @new_array : shared;
my %new_hash : shared;
my %hoh : shared;
@new_array = ("tom", "jerry");
%new_hash = (itchy => "Scratchy");
%hoh = hoh(@new_array);
my %anon : shared;
$hash{$string} = \%anon;
$hash{$string}{"Grenade"} = \@new_array;
$hash{$string}{"Pipe bomb"} = \%new_hash;
$hash{$string}{"jc"} = \%hoh;
push @out_array, \%hash;
return;
}
sub hoh
{
my %hoh;
foreach my $item (@_) {
$hoh{"jeepers"}{"creepers"} = $item;
}
return %hoh;
}
答案 0 :(得分:3)
问题在于您尝试存储对共享变量中未共享的内容的引用。您需要使用前面提到的share
,或者需要序列化数据结构。
答案 1 :(得分:1)
#!/perl/bin/perl
use strict;
use threads;
use threads::shared;
my %hm_n2g:shared = ();
my $row = &share([]);
$hm_n2g{"aa"}=$row;
$row->[0]=1;
$row->[1]=2;
my @arr = @{$hm_n2g{"aa"}};
print @arr[0]." ".@arr[1]."\n";
#If you want to lock the hash in a thread-subroutine
{
lock(%hm_n2g)
}