Question

我的代码适用于一个单词，因此搜索器Proc工作正常。我试图通过将它们存储在数组中然后将每个单词传递给proc并将它们放在一起来使多个单词工作，但是当我测试诸如“eat pie”之类的东西时，它会返回它。你能告诉我我做错了什么吗？

Failures:

1) translate translates two words
 Failure/Error: s.should == "eatay iepay"
   expected: "eatay iepay"
        got: "eat pieay eat pieayay" (using ==)
 # ./04_pig_latin/pig_latin_spec.rb:41:in `block (2 levels) in <top (required)>'

继承我的代码：

def translate(x)
  array = x.split(' ')  
  searcher = Proc.new{ 
    if x.index(/[aeiou]/) == 0
      x = x + "ay"
    elsif x[0..1] == "qu"
      first = x.chr
      x.reverse!.chop!.reverse!
      second = x.chr
      x.reverse!.chop!.reverse!
      x = x + first + second + "ay"
   elsif x.index(/[aeiou]/) == 1
     first = x.chr
     x.reverse!.chop!.reverse!
     x = x + first + "ay"
  elsif x[1..2] == "qu"
     first = x.chr
     x.reverse!.chop!.reverse!
     second = x.chr
     x.reverse!.chop!.reverse!
     third = x.chr
     x.reverse!.chop!.reverse!
     x = x + first + second + third +"ay"
  elsif x.index(/[aeiou]/) == 2
    first = x.chr.chr
    x.reverse!.chop!.reverse!
    second = x.chr
    x.reverse!.chop!.reverse!
    x = x + first + second + "ay"
 elsif x.index(/[aeiou]/) == 3
   first = x.chr
   x.reverse!.chop!.reverse!
   second = x.chr
   x.reverse!.chop!.reverse!
   third = x.chr
   x.reverse!.chop!.reverse!
   x = x + first + second + third +"ay"
else
  x
end
}
if array.count == 1
  searcher.call
  return x
else
  return array.collect(&searcher).join(' ')
end
end

Answer 1

问题在于，您指的是x中的searcher，该x对于传递到translate的参数Proc已关闭，当您真正想要做什么时是一次处理一个数组的每个元素。

我更改了代码的结构以便更容易推理 - 通过消除匿名#!/usr/bin/env ruby def translate_word(x) if x.index(/[aeiou]/) == 0 x = x + "ay" elsif x[0..1] == "qu" first = x.chr x.reverse!.chop!.reverse! second = x.chr x.reverse!.chop!.reverse! x = x + first + second + "ay" elsif x.index(/[aeiou]/) == 1 first = x.chr x.reverse!.chop!.reverse! x = x + first + "ay" elsif x[1..2] == "qu" first = x.chr x.reverse!.chop!.reverse! second = x.chr x.reverse!.chop!.reverse! third = x.chr x.reverse!.chop!.reverse! x = x + first + second + third +"ay" elsif x.index(/[aeiou]/) == 2 first = x.chr.chr x.reverse!.chop!.reverse! second = x.chr x.reverse!.chop!.reverse! x = x + first + second + "ay" elsif x.index(/[aeiou]/) == 3 first = x.chr x.reverse!.chop!.reverse! second = x.chr x.reverse!.chop!.reverse! third = x.chr x.reverse!.chop!.reverse! x = x + first + second + third +"ay" else x end end words = ARGV[0].split(' ').map { |word| translate_word(word) }.join(' ') puts words并使用惯用的Ruby映射来处理字符串 - 无论是一个还是多个单词。

chmod +x pig_latin

./pig_latin "eat pie" ./pig_latin "eat"验证：

{{1}}

在红宝石中创建一个猪拉丁语翻译，有多个单词的麻烦

1 个答案: