Question

我正在研究The Odin Project中的pig_latin_spec示例，并且在处理特殊情况时遇到一些困难，其中一个单词包含“qu”，并且这些字符需要被视为一个音素。例如“quiet”=＆gt; “ietquay”和“square”=＆gt; “aresquay”。

以下是违规if声明：

if word.include? "qu"
    start_index = word.index("q")
    prefix = word[0..(start_index+1)] + "ay"
    pig_word = word[(start_index+2)..-1] + prefix
end

这会产生“ietquay”而不是“isququay”。相反，我得到“uaresqay”。我在俯瞰什么？

以下是整个计划：

def translate(input)
all_words = []
pig_word = ""
input.split.map do |word, i|
    if 'aeiou'.include? word[0]
        pig_word = word + "ay"
    else
        prefix = word[0] + "ay"
        pig_word = word[1..-1] + prefix
        if word.include? "qu"
            start_index = word.index("q")
            prefix = word[0..(start_index+1)] + "ay"
            pig_word = word[(start_index+2)..-1] + prefix
        end
        unless 'aeiou'.include? word[1]
            prefix = word[0..1] + "ay"
            pig_word = word[2..-1] + prefix
            unless 'aeiou'.include? word[2]
                prefix = word[0..2] + "ay"
                pig_word = word[3..-1] + prefix
            end
        end
    end
    all_words << pig_word
end
"#{[all_words].join(" ")}"
end

Answer 1

正在运行“qu”的特殊外壳，但后来用unless中的逻辑替换了这个条件：

   'aeiou'.include? word[1]

因为false的条件为word = "square"（因为“q”不在“aeiou”中）。

快速修补/修复是使用if...elsif使两个竞争条件块互斥，当单词包含“qu”时，它将不会进一步检查。

    if word.include? "qu"
        start_index = word.index("q")
        prefix = word[0..(start_index+1)] + "ay"
        pig_word = word[(start_index+2)..-1] + prefix
    elsif ! 'aeiou'.include? word[1]
        prefix = word[0..1] + "ay"
        pig_word = word[2..-1] + prefix
        unless 'aeiou'.include? word[2]
            prefix = word[0..2] + "ay"
            pig_word = word[3..-1] + prefix
        end
    end

请注意，这可能无法带来完美的翻译，它只会解决您在此处提出的问题。

Answer 2

实现Neil的建议编辑，这是完整功能的代码：

def translate(input)
all_words = []
pig_word = ""
input.split.map do |word, i|

    first_vowel = word.index(/[aeiou]/) #dat first vowel occurence

    if first_vowel == 0 #words that begin with a vowel
        pig_word = word + "ay"


    elsif word.include? "qu" #words that don't begin with a vowel but include "qu".
        first_vowel = word.index(/[aeio]/) #first vowel not counting "u"
        start_index = word.index("q")
        prefix = word[0..(first_vowel-1)] + "ay"
        pig_word = word[first_vowel..-1] + prefix
    end


    if first_vowel >= 1 #words that don't begin with vowels or have "qu"
        prefix = word[0..first_vowel-1] + "ay" 
        pig_word = word[first_vowel..-1] + prefix
    end 


    all_words << pig_word
end
"#{[all_words].join(" ")}" 
end

Pig-latin翻译不规则地解析“qu”

2 个答案: