Question

我已经绘制了图表，我得到了一些代码

fs = 100; %freq 100hz
N = length(pbcg); %data length, before that do a pbcg=load('pbcg.txt')
duration_in_seconds = N/fs;
duration_in_minutes = duration_in_seconds/60;
BPM_avg = beat_count/duration_in_minutes;

fid = fopen('y1.txt','a'); %txt naming and append

%count the dominant peaks in the signal
for k = 2 : length(pbcg)-1
    if (pbcg(k) > pbcg(k-1) && pbcg(k) > pbcg(k+1) && pbcg(k) > 1)
        beat_count = beat_count + 1;
    end
    fprintf(fid,  'x_axis%i\t ', k); %open writer
    fprintf(fid,  'BPM%i\n ', BPM_avg); %open writer
end
disp(BPM_avg); %display the BPM
fclose(fid); %close writer

绘制图形的图像在这里（没有插入img的声誉）... https://skydrive.live.com/embed?cid=0525DA685954952E&resid=525DA685954952E%21407&authkey=ALmvTzzQ7Xer2Do

我想知道的是，你可以看到最高的是11peak，我如何在峰值中获得'价值'？因为我想知道如何获得y轴值或计算值。

Answer 1

我这样做就像@Adiel教的那样......

%determine the bpm

beat_count = 0;
fs = 100; %freq 100hz
N = length(pbcg); %data length, before that do a pbcg=load('pbcg.txt')
duration_in_seconds = N/fs;
duration_in_minutes = duration_in_seconds/60;
BPM_avg = beat_count/duration_in_minutes;

fid = fopen('y1.txt','a'); %txt naming and append

%count the dominant peaks in the signal
for k = 2 : length(pbcg)-1
    if (pbcg(k) > pbcg(k-1) && pbcg(k) > pbcg(k+1) && pbcg(k) > 1)
    beat_count = beat_count + 1;
    peaks(beat_count)=pbcg(k);
end
fprintf(fid,  'x_axis%i\t ', k); %open writer
fprintf(fid,  'BPM%i\n ', BPM_avg); %open writer
end

disp(BPM_avg); %display the BPM
fclose(fid); %close writer

并从matlab命令输入'peak'，它显示了我的y轴值的总峰数。因为我确实需要清除“beat_count”和“峰值”，因为每当我'运行'它将使数据量翻倍的功能

matlab峰值（找到峰但想知道值）

1 个答案: