Eclipse在以下代码中给出了警告:
public int getTicket(int lotteryId, String player) {
try {
c = DriverManager.getConnection("jdbc:mysql://" + this.hostname + ":" + this.port + "/" + this.database, this.user, this.password);
int ticketNumber;
PreparedStatement p = c.prepareStatement(
"SELECT max(num_ticket) " +
"FROM loteria_tickets " +
"WHERE id_loteria = ?"
);
p.setInt(1, lotteryId);
ResultSet rs = p.executeQuery();
if (rs.next()) {
ticketNumber = rs.getInt(1);
} else {
ticketNumber = -1;
}
ticketNumber++;
p = c.prepareStatement(
"INSERT INTO loteria_tickets " +
"VALUES (?,?,?,?)");
p.setInt(1, lotteryId);
p.setInt(2, ticketNumber);
p.setString(3, player);
p.setDate(4, new java.sql.Date((new java.util.Date()).getTime()));
p.executeUpdate();
return ticketNumber;
} catch (Exception e) {
e.printStackTrace();
} finally {
if (c != null) {
try {
c.close();
} catch (SQLException e) {
e.printStackTrace();
}
}
return -1;
}
}
我的代码出了什么问题?
答案 0 :(得分:116)
从中删除return语句。 最终块被认为是清理块,通常不会返回它。
答案 1 :(得分:20)
来自return
"的finally
覆盖"进一步例外。
public class App {
public static void main(String[] args) {
System.err.println(f());
}
public static int f() {
try {
throw new RuntimeException();
} finally {
return 1;
}
}
}
1
答案 2 :(得分:8)
一般来说,finally
块永远不应该有一个return语句,因为它会覆盖其他return
- 语句或Exceptions
。
如需进一步阅读并详细解答其背景,请参阅问题
答案 3 :(得分:4)
在return
块中使用throw
和finally
语句,您将收到警告,例如,您将获得与以下最终块相同的警告:
...
}finally{
throw new RuntimeException("from finally!");
}
...
答案 4 :(得分:0)
如果您没有任何catch
块,那么您的finally
块必须直接嵌套在彼此内部。它只是捕获一个异常,该异常使您的代码可以继续经过try / catch / finally块的末尾。如果您没有捕获到异常,那么在finally块之后就不会有任何代码!
您可以了解其工作原理with this example on Repl.it
testing if 0 > 5 ?
try1
try2
finally3
catch1
finally2
After other finally
finally1
end of function
testing if 10 > 5 ?
try1
try2
try3
success
finally3
finally2
finally1
class Main {
public static void main(String[] args) {
isGreaterThan5(0);
isGreaterThan5(10);
}
public static boolean isGreaterThan5(int a)
{
System.out.println();
System.out.println("testing if " + a + " > 5 ?");
try
{
System.out.println("try1");
try
{
System.out.println("try2");
try
{
if (a <= 5)
{
throw new RuntimeException("Problems!");
}
System.out.println("try3");
System.out.println("success");
return true;
}
finally
{
System.out.println("finally3");
}
}
catch (Exception e)
{
System.out.println("catch1");
}
finally
{
System.out.println("finally2");
}
System.out.println("After other finally");
}
catch (Exception e)
{
System.out.println("failed");
return false;
}
finally
{
System.out.println("finally1");
}
System.out.println("end of function");
return false;
}
}