如何从非PyQt类发出信号？

时间：2013-07-04 03:05:05

标签： python python-2.7 pyqt pyqt4 twisted

我正在使用twisted和PyQt在python中编写应用程序。我面临的问题是，当我的扭曲代码中的函数被执行时，我必须在GUI中打印一行，我试图通过发出信号（非PyQt类）来实现这一点。这似乎不起作用，我怀疑扭曲的事件循环正在为PyQt搞砸事情。因为closeEvent信号没有被程序捕获。

以下是代码段：

from PyQt4 import QtGui, QtCore
import sys
from twisted.internet.protocol import Factory, Protocol
from twisted.protocols import amp
import qt4reactor

class register_procedure(amp.Command):
    arguments = [('MAC',amp.String()),
                        ('IP',amp.String()),
                        ('Computer_Name',amp.String()),
                        ('OS',amp.String())
                        ]
    response = [('req_status', amp.String()),
         ('ALIGN_FUNCTION', amp.String()),
                         ('ALIGN_Confirmation', amp.Integer()),
                         ('Callback_offset',amp.Integer())
                        ]

class Ui_MainWindow(QtGui.QMainWindow):

    def __init__(self,reactor, parent=None):
        super(Ui_MainWindow,self).__init__(parent)
        self.reactor=reactor
        self.pf = Factory()
        self.pf.protocol = Protocol
        self.reactor.listenTCP(3610, self.pf) # listen on port 1234

        def setupUi(self,MainWindow):
        MainWindow.setObjectName(_fromUtf8("MainWindow"))
        MainWindow.resize(903, 677)
        self.centralwidget = QtGui.QWidget(MainWindow)
        sizePolicy = QtGui.QSizePolicy(QtGui.QSizePolicy.Expanding, QtGui.QSizePolicy.Expanding)
        sizePolicy.setHorizontalStretch(0)
        sizePolicy.setVerticalStretch(0)
        sizePolicy.setHeightForWidth(self.centralwidget.sizePolicy().hasHeightForWidth())
        self.centralwidget.setSizePolicy(sizePolicy)

        self.create_item()


        self.retranslateUi(MainWindow)
        self.connect(self, QtCore.SIGNAL('triggered()'), self.closeEvent)
        QtCore.QObject.connect(self,QtCore.SIGNAL('registered()'),self.registered)
        QtCore.QMetaObject.connectSlotsByName(MainWindow)

    def retranslateUi(self, MainWindow):
        MainWindow.setWindowTitle(_translate("MainWindow", "MainWindow", None))
        self.pushButton_4.setText(_translate("MainWindow", "Delete System ", None))
        self.pushButton.setText(_translate("MainWindow", "Add System", None))
        self.label_2.setText(_translate("MainWindow", "SYSTEM STATUS", None))
        self.label.setText(_translate("MainWindow", "Monitoring Output", None))


    def registered(self):# this function is not being triggered
        print "check" 
        self.textbrowser.append()

    def closeEvent(self, event):#neither is this being triggered
        print "asdf"
        self.rector.stop()
        MainWindow.close()
        event.accept()


class Protocol(amp.AMP):
    @register_procedure.responder
    def register_procedure(self,MAC,IP,Computer_Name,OS):
        self.bridge_conn=bridge()
        cursor_device.execute("""select * FROM devices where MAC = ?;""",[(MAC)])
        exists_val=cursor_device.fetchone()
        cursor_device.fetchone()
        print "register"
        if not exists_val== "":
            cursor_device.execute("""update devices set IP= ? , Computer_name= ? , OS = ?  where MAC= ?;""",[IP,Computer_Name,OS,MAC])
            QtCore.QObject.emit( QtCore.SIGNAL('registered')) # <--emits signal
            return {'req_status': "done" ,'ALIGN_FUNCTION':'none','ALIGN_Confirmation':0,'Callback_offset':call_offset(1)}
        else:
            cursor_device.execute("""INSERT INTO devices(Mac,Ip,Computer_name,Os) values (?,?,?,?);""",[MAC,IP,Computer_Name,OS])
            QtCore.QObject.emit( QtCore.SIGNAL('registered'))#<--emits signal
            return {'req_status': "done" ,'ALIGN_FUNCTION':'main_loop()','ALIGN_Confirmation':0,'Callback_offset':0}



if  __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)

    try:
        import qt4reactor
    except ImportError:
        from twisted.internet import qt4reactor
    qt4reactor.install()

    from twisted.internet import reactor
    MainWindow = QtGui.QMainWindow() # <-- Instantiate QMainWindow object.
    ui = Ui_MainWindow(reactor)
    ui.setupUi(MainWindow)
    MainWindow.show()
    reactor.run()

3 个答案:

答案 0 :(得分：3)

这是我在我的一个代码中用于从QGraphicsItems发送信号的原因（因为它们不是从QObject派生的，并且默认情况下不能发送/接收信号）。它基本上是Radio-answer的简化版本。 

from PyQt4 import QtGui as QG
from PyQt4 import QtCore as QC

class SenderObject(QC.QObject):
    something_happened = QC.pyqtSignal()

SenderObject是一个从QObject派生的小类，您可以放置​​所需的所有信号。在这种情况下，只定义了一个。

class SnapROIItem(QG.QGraphicsRectItem):
    def __init__(self, parent = None):
        super(SnapROIItem, self).__init__(parent)
        self.sender = SenderObject()
    def do_something_and_emit(self):
        ...
        self.sender.something_happened.emit()

在非QObject类中，您添加SenderObject作为sender变量。在使用非QObject类的任何地方，您可以将sender的信号连接到您需要的任何信号。

class ROIManager(QC.QObject):
    def add_snaproi(self, snaproi):
        snaproi.sender.something_happened.connect(...)

<强>更新

完整的代码就是这样，应该打印出“发生了什么......”：

from PyQt4 import QtGui as QG
from PyQt4 import QtCore as QC

class SenderObject(QC.QObject):
    something_happened = QC.pyqtSignal()

class SnapROIItem(QG.QGraphicsItem):
    def __init__(self, parent = None):
        super(SnapROIItem, self).__init__(parent)
        self.sender = SenderObject()
    def do_something_and_emit(self):
        self.sender.something_happened.emit()

class ROIManager(QC.QObject):
    def __init__(self, parent=None):
        super(ROIManager,self).__init__(parent)
    def add_snaproi(self, snaproi):
        snaproi.sender.something_happened.connect(self.new_roi)
    def new_roi(self):
        print 'Something happened in ROI!'

if __name__=="__main__":)
    roimanager = ROIManager()
    snaproi = SnapROIItem()
    roimanager.add_snaproi(snaproi)
    snaproi.do_something_and_emit()

更新2

而不是

QtCore.QObject.connect(self,QtCore.SIGNAL('registered()'),self.registered)

你应该：

protocol.sender.registered.connect(self.registered)

这意味着您还需要抓住protocol中的self.pf实例（顺便说一下，您导入Protocol然后自己定义它吗？）

在Protocol类中而不是

QtCore.QObject.emit( QtCore.SIGNAL('registered')

首先，您需要在协议中实例化SenderObject。 

class Protocol(amp.AMP):
    def __init__( self, *args, **kw ):
       super(Protocol, self).__init__(*args, **kw)
       self.sender = SenderObject()

然后，在register_procedure中通过sender发出信号：      self.sender.registered.emit（）

要使所有这些工作，您必须将SenderObject定义为：

class SenderObject(QC.QObject):
    registered = QC.pyqtSignal()

答案 1 :(得分：1)

这是一篇很老的帖子，但它帮助了我。这是我的版本。一个不是QObject的项目用信号通知另外两个非QObject来运行它们的方法。

from PyQt4 import QtGui, QtCore

class Signal(object):
    class Emitter(QtCore.QObject):
        registered = QtCore.pyqtSignal()
        def __init__(self):
            super(Signal.Emitter, self).__init__()

    def __init__(self):
        self.emitter = Signal.Emitter()

    def register(self):
        self.emitter.registered.emit()

    def connect(self, signal, slot):
        signal.emitter.registered.connect(slot)

class item(object):
    def __init__(self, name):
        self.name = name
        self.signal = Signal()

    def something(self):
        print self.name, ' says something'

>>> itemA = item('a')
>>> itemB = item('b')
>>> itemC = item('c')
>>> itemA.signal.connect(itemA.signal, itemB.something)
>>> itemA.signal.connect(itemA.signal, itemC.something)
>>> itemA.signal.register()

b  says something
c  says something

答案 2 :(得分：0)

两个基本问题是：

1）必须知道信号的发送者和接收者

在Qt中考虑一个更常见的情况，你可能有多个按钮，每个按钮都有一个“点击”信号。插槽需要知道单击了哪个按钮，因此捕获通用信号没有多大意义。

和2）信号必须来自QObject。

话虽如此，我不确定规范的实现是什么。这是一种方法，使用您在之前的帖子中拥有的Bridge的概念，以及Protocol内部的特殊Emitter类。运行此代码只会在调用protocol.register（）时打印“Working it”。

from PyQt4 import QtGui, QtCore
import sys

class Ui_MainWindow(QtGui.QMainWindow):
    def __init__(self):
        super(Ui_MainWindow, self).__init__()

    def work(self):
        print "Working it"

class Protocol(object):
    class Emitter(QtCore.QObject):
        registered = QtCore.pyqtSignal()
        def __init__(self):
            super(Protocol.Emitter, self).__init__()

    def __init__(self):
        self.emitter = Protocol.Emitter()

    def register(self):
        self.emitter.registered.emit()

class Bridge(QtCore.QObject):
    def __init__(self, gui, protocol):
        super(Bridge, self).__init__()
        self.gui = gui
        self.protocol = protocol

    def bridge(self):
        self.protocol.emitter.registered.connect(self.gui.work)

app = QtGui.QApplication(sys.argv)
gui = Ui_MainWindow()
protocol = Protocol()
bridge = Bridge(gui, protocol)
bridge.bridge()
#protocol.register() #uncomment to see 'Working it' printed to the console
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