我正在尝试将多个文件上传到目录。 我已经“编写”的代码适用于一个文件,但是当我尝试上传多个文件时,它不起作用。我试图确定故障的位置,我相信它与计数有关。虽然当我试图回显有多少文件被计算时,无论我选择了多少文件,我总是得到'1'。我知道这只适用于一个文件,因为我返回的变量总是'1',因此只适用于一个文件。
通过post方法收集我正在使用html表单的文件 HTML:
<form id="upload" action="upload.php" method="POST" enctype="multipart/form-data">
<fieldset>
<legend>HTML File Upload</legend>
<input type="hidden" id="MAX_FILE_SIZE" name="MAX_FILE_SIZE" value="300000" />
<div>
<label for="fileselect">Files to upload:</label>
<input type="file" id="fileselect" name="fileselect[]" multiple="multiple" />
<div id="filedrag">or drop files here</div>
</div>
<div id="submit">
<button type="submit">Upload Files</button>
</div>
</fieldset>
</form>
我正在使用的javascript启用拖放功能,源自: http://www.sitepoint.com/html5-file-drag-and-drop/
罪魁祸首 PHP:if(isset($_FILES['fileselect']['tmp_name'])) {
// Number of uploaded files
$num_files = count($_FILES['fileselect']['tmp_name']);
echo $num_files;
/** loop through the array of files ***/
for($i=0; $i <= $num_files;$i++) {
// check if there is a file in the array
if(!is_uploaded_file($_FILES['fileselect']['tmp_name'][$i])) {
$messages[] = 'No file uploaded';
}
else {
$unique = substr(number_format(time() * rand(),0,'',''),0,10);
$newImg = "img".$unique;
$filename = basename($_FILES['file']['name'][$i]);
$extension = pathinfo($filename, PATHINFO_EXTENSION);
//$new = md5($filename).'.'.$extension;
$the_file_type = $_FILES['fileselect']['type'][$i];
$the_file_size = $_FILES['fileselect']['size'][$i] / 1024;
$the_file_name = $_FILES['fileselect']['name'][$i];
$ok=1;
//This is our size condition
if ($uploaded_size > 350000) {
$messages[] = "Your file is too large.<br>";
$ok=0;
}
//This is our limit file type condition
if ($uploaded_type =="text/php") {
$messages[] = "No PHP files<br>";
$ok=0;
}
//Here we check that $ok was not set to 0 by an error
if ($ok==0) {
$messages[] = "Sorry your file was not uploaded";
}
//If everything is ok we try to upload it
else {
if(move_uploaded_file($_FILES['fileselect']['tmp_name'][$i], "uploads/{$newImg}")) {
echo "The file ". basename( $_FILES['uploadedfile']['name'][$i]). " has been uploaded";
echo "<br />";
//echo $the_file_type;
//echo "<br />";
//echo $unique;
//echo "<span>schmeckle!</span>";
//echo "<br />";
//echo $the_file_size;
//echo "<br />";
//echo $the_file_name;
$insertSQL = "INSERT INTO interviews_media_images SET ";
$insertSQL .= "fileType='$the_file_type', ";
$insertSQL .= "fileRef='$newImg', ";
$insertSQL .= "fileSize='$the_file_size', ";
$insertSQL .= "fileName='$the_file_name' ";
echo $insertSQL;
//mysql_query( $insertSQL);
//echo mysql_error();
} else {
$messages[] = "Sorry, there was a problem uploading your file.";
}
}
}
}
}
答案 0 :(得分:0)
我使用以下内容创建了一个文件,运行PHP版本5.5.15并且它正确计数:
<?php
if(isset($_FILES['fileselect']['tmp_name']))
{
echo "<pre>"; print_r($_FILES); echo "</pre>";
echo "Number of files uploaded: " . count($_FILES['fileselect']['name']);
}
?>
<form id="upload" action="files_upload.php" method="POST" enctype="multipart/form-data">
<fieldset>
<legend>HTML File Upload</legend>
<input type="hidden" id="MAX_FILE_SIZE" name="MAX_FILE_SIZE" value="300000" />
<div>
<label for="fileselect">Files to upload:</label>
<input type="file" id="fileselect" name="fileselect[]" multiple="multiple" />
<div id="filedrag">or drop files here</div>
</div>
<div id="submit">
<button type="submit">Upload Files</button>
</div>
</fieldset>
</form>
答案 1 :(得分:0)
您的代码在我的情况下运行,$ num_files在count之后返回true值。
还有一件事要从for循环中删除' = '并像这样写
for( $i=0; $i<$num_files; $i++)
如果你使用 $ i&lt; = $ num_files ,它会给你一个通知。
假设您正在选择3个文件而您正在设置 $ i&lt; = $ num_files 。
因此,循环从0开始,当您选择3个文件时,它会继续4次
0 1 2 3
你可以看到循环继续4次,但它没有文件
$_FILES['filename']['tmp_name'][3].
我希望这会对你有帮助......
抱歉我的英文。