按计数排序不正确排序记录？

Question

我正在使用MySQL。我有两张桌子，我附上了两张桌子的图像？当我按计数应用ORDER然后查询从数据库检索结果但没有正确排序时，我不知道我在做什么错？我在堆栈溢出中搜索了一些类似的问题，但我仍面临同样的问题。

我试过这些但没有成功

    $sql    = "Select * from gr_groups";
    $result = $db->select($sql);
    for($j = 0; $j < count($result); $j++)
    {
        $mygrp_id = $result[$j]['id'];

        $query       = "Select * from gr_group_memberships where group_id =".$mygrp_id." ORDER BY COUNT(receiver_id) DESC";
        $exec_query  = $db->select($query);
        echo $exec_query[0]['group_id'];
    }

提前致谢？

Answer 1

仅

ORDER BY receiver_id DESC 

将解决问题。

<强>更新

尝试加入他们 -

SELECT * FROM gr_groups g 
LEFT JOIN gr_group_memberships gm on gm.group_id = g.id
ORDER BY COUNT(gm.receiver_id) DESC

这将获取具有按计数排序的所有成员资格的组。

Answer 2

尝试如下;

$query = "Select * from gr_group_memberships where group_id = ".$mygrp_id." ORDER BY receiver_id DESC";

Answer 3

你可以计算和排序，但这样会更好

 SELECT *,count(receiver_id) as total_receivers 
  FROM gr_group_memberships 
  WHERE group_id =".$mygrp_id." 
  GROUP BY receiver_id
  ORDER BY receiver_id DESC;

Answer 4

尝试此查询：

$query = "Select a.* from gr_group_memberships a 
          join( select receiver_id,count(receiver_id) as count1
          from  gr_group_memberships group by receiver_id) b on
          a.receiver_id=b.receiver_id  where a.group_id =".$mygrp_id."
          ORDER BY count1 DESC";

Answer 5

试试这个

SELECT count(receiver_id) as total_receiver FROM gr_group_memberships
INNER JOIN gr_group on gr_group_memberships.group_id = gr_group.id
GROUP BY gr_group_memberships.receiver_id
ORDER BY gr_group_memberships.receiver_id DESC

我认为它会按你想要的方式运作