Question

我的代码是：

SELECT 
    Sum(DR.TimeOfWork) "Skutečnost",
    SU.name "Jmeno"
FROM DevTimeRecords DR
left join SecurityUsers SU on SU.ID=DR.Worker_ID
left join DevBugs DB on DB.ID=DR.DevDocument_ID
left join DevProducts DPR on DPR.ID=DB.Product_ID
left join DevParts DPA on DPA.ID=DB.Part_ID
where
    SU.id = '@{_osoba}'
    and DPR.Code = 'ZP'
    and DPA.Code='A' 
    and not(DB.Status_ID IN ('TUPER00101','UUPER00101'))
group by
    SU.Name
order by
    SU.Name ASC

我需要添加列，其中将计算工作日直到今天。例如：到今天这个列的日期返回数字18（月中27天 - 周末）。如何添加此列？

Answer 1

我处理这个问题的方法是简单地利用我创建的“日历”表，其中包含2100年的日期，以及表示工作日为真/假的字段。

技术含量低但效果好 - 您可以将假期标记为工作日，如果您的公司决定更改假期，则更改一个表而不是计算它的所有语句。

Answer 2

我最近开始使用递归CTE SQL根据需要生成这样的数据。下面的SQL生成一个包含开始日期和结束日期的数据日历。我添加了一个额外的列来指示周末天数，如果日期在current_date之前，它是星期六或星期日。

with recursive calendar (dte,num) as (
    select CAST('1/1/2013' /* Start Date */ as date) as dte, CAST(1 as integer) as num from rdb$database
    union all
    select DATEADD(day,1,calendar.dte) as dte, calendar.num+1 as num from calendar
    where DATEADD(day,1,calendar.dte) <= '1/31/2013' /* End Date */
)
select
    calendar.*,
    EXTRACT(weekday FROM calendar.dte) as wkday,
    IIF(calendar.dte <= current_date and EXTRACT(weekday FROM calendar.dte) IN (0,6) /* Sunday & Saturday */,1,0) as wkdaytodate
from calendar

通过一些修改，您可以获得该月的单个结果。

with recursive calendar (dte,num) as (
    select CAST('1/1/2013' /* Start Date */ as date) as dte, CAST(1 as integer) as num from rdb$database
    union all
    select DATEADD(day,1,calendar.dte) as dte, calendar.num+1 as num from calendar
    where DATEADD(day,1,calendar.dte) <= '1/31/2013' /* End Date */
)
select
    MIN(calendar.dte) as dte,
    SUM(IIF(calendar.dte <= current_date and EXTRACT(weekday FROM calendar.dte) IN (0,6) /* Sunday & Saturday */,1,0)) as wkdaytodate
from calendar

如果您需要它更小，您可以简单地将其定义为单列。

select
    'test' as text,
    (
        with recursive calendar (dte,num) as (
            select CAST('1/1/2013' /* Start Date */ as date) as dte, CAST(1 as integer) as num from rdb$database
            union all
            select DATEADD(day,1,calendar.dte) as dte, calendar.num+1 as num from calendar
            where DATEADD(day,1,calendar.dte) <= '1/31/2013' /* End Date */
        )
        select
            SUM(IIF(calendar.dte <= current_date and EXTRACT(weekday FROM calendar.dte) IN (0,6) /* Sunday & Saturday */,1,0)) as wkdaytodate
        from calendar
    ) as numofweekenddays

from rdb$database

其他人表示，除了“工作日是星期一至星期五”的简单规则之外，任何事情都应该存放在日历表中，我同意这一点。

一个月的工作日

2 个答案: