Question

我有一个这样的清单：

[[(2L,)], [(3L,)]]

我想转换成如下列表：

[2, 3]

我该怎么做？

Answer 1

使用列表推导：

如果元组只包含1个项目：

>>> lis = [[(2L,)], [(3L,)]]
>>> [ y[0] for x in lis for y in x]
[2L, 3L]

如果元组包含多个项目：

>>> [z for x in lis for y in x for z in y]
[2L, 3L]

这适用于任何数量的嵌套：

from collections import Iterable
def flatten(collection):
  for element in collection:
    if isinstance(element, Iterable) and not isinstance(element, basestring):
      for x in flatten(element):
        yield x
    else:
      yield element
>>> list(flatten(lis))
[2L, 3L]
>>> lis = [[(2L,)], [(3L,(4,(5,)))]]
>>> list(flatten(lis))
[2L, 3L, 4, 5]

Answer 2

使用列表推导并将long转换为int：

>>> L = [[(2L,)], [(3L,)]]
>>> result = [int(y[0]) for x in L for y in x]
>>> result
[2, 3]

Answer 3

要删除尾随的L，请使用int()：

>>> L = [[(2L,)], [(3L,)]]
>>> [int(i[0][0]) for i in L]
[2, 3]

Answer 4

>>> d = [[(2L,)], [(3L,)]]
>>> map(lambda x: x[0][0], d)
[2L, 3L]

转换此列表，仅在Python中列表中的元组？

4 个答案: