Question

我有以下元组（list_permutation）：

[(1,), (2,), (3,), (1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]

我想将其转换为如下所示的列表：

[[1],[2],[3],[1,2],[1,3]]...

这是我已经尝试过的代码：

result = [int(x) for x, in list_permutation]
print(result)

但是我遇到了这个错误：

---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-63-fc7f88d67875> in <module>
----> 1 result = [int(x) for x, in list_permutation]
      2 print(result)

<ipython-input-63-fc7f88d67875> in <listcomp>(.0)
----> 1 result = [int(x) for x, in list_permutation]
      2 print(result)

ValueError: too many values to unpack (expected 1)

Answer 1

l = [(1,), (2,), (3,), (1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]
new_l = [list(x) for x in l]
print(new_l)

这将产生[[1], [2], [3], [1, 2], [1, 3], [2, 1], [2, 3], [3, 1], [3, 2]]。

Answer 2

您可以使用内置的地图功能：

l = [(1,), (2,), (3,), (1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]
l = list(map(list, l))
print(l)

这应该给你 [[1], [2], [3], [1, 2], [1, 3], [2, 1], [2, 3], [3, 1], [3, 2]]

Answer 3

使用地图可以轻松实现

perm = [(1,), (2,), (3,), (1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]
perm_as_list = map(list, perm)

下面的输出

In [1]: perm = [(1,), (2,), (3,), (1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]
In [2]: perm_as_list = map(list, perm)
In [3]: perm_as_list
Out[3]: [[1], [2], [3], [1, 2], [1, 3], [2, 1], [2, 3], [3, 1], [3, 2]]

Answer 4

list函数可以将元组转换为list 您有一个元组列表，所以如下：

list_permutation=[(1,), (2,), (3,), (1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]
result = [list(x) for x in list_permutation]

如何将该元组转换为列表

4 个答案: