Question

我有一个在codeigniter中开发的网站，我想要检索特定T恤的评论。我有一个像这样的桌子：

- id
- user_id
- name
- created
- modified

表tee_comments就是这样：

- id
- user_id
- tee_id
- created
- modified

我已完成此查询：

 $this->db->select('*,tee.id as id,tee.created as created, tee_comments.id as tee_comments_id, tee_comments.created as tee_comments_created, tee_comments.modified as tee_comments_modified');
    $this->db->from('tee');
    $this->db->join('tee_comments', 'tee_comments.tee_id = tee.id','left outer');
    $this->db->order_by("tee.created", "desc");
    $query = $this->db->get();

通过这个查询，我检索了两排三通，因为我在那个发球台上有两条评论。

我的目标是只检索一行内部有一系列评论，如：

tee{
  id,
  name,
  created,
  modified
  comment{
     [0]
         id,
         tee_id,
         comment,
         created,
         modified
     [1]
         id,
         tee_id,
         comment,
         created,
         modified
  }
}

我尝试过加入： - 剩下 - 对 - 左外 - 右外

但是没有解决问题，有没有办法做到这一点？感谢

Answer 1

我喜欢CodeIgniter！我经常使用它！这里有2个非常简单的选项：

一种方法是使用limit。

$this->db->select('*,tee.id as id,tee.created as created, tee_comments.id as tee_comments_id, tee_comments.created as tee_comments_created, tee_comments.modified as tee_comments_modified');
$this->db->join('tee_comments', 'tee_comments.tee_id = tee.id','left outer');
$this->db->order_by("tee.created", "desc");
$query = $this->db->limit(1)->get('tee');

另一种方法是获取results Array

中的第一项

$query = $this->db->get();
$results = $query->result(); // gets return as an array
$row = $results[0]; // will be first row in results array

请记住，$row将以object(stdClass)的形式返回，这意味着您必须像$row->column_name一样从中检索内容。

我打算在电话会议后使用一个方便的小片段。它会使行Object成为Array。

$results = $db->get('tee')->result(); // snippet comes after you have result array
// snippet here
foreach ($r as $k => $v) { $results[$k] = array(); foreach ($v as $kk => $vv) { $results[$k][$kk] = $vv != "NULL" ? trim($vv) : ""; } }

Answer 2

使用$this->db->limit(1)检索单个记录。

根据this question上接受的答案，您可能需要将限制声明放在选择之前：

$this->db->limit(1);
$this->db->select('*,tee.id as id,tee.created as created, tee_comments.id as tee_comments_id, tee_comments.created as tee_comments_created, tee_comments.modified as tee_comments_modified');
$this->db->from('tee');

Answer 3

选项一：

for ($i = 0; $i < count($records); $i++)
{
 $data = $records[$i];
 // work with date.
 if($i == 1)
   break;
}

选项二：只需将第一行分配给var。

$row = $records['tee']['comment'][0];

仅检索一行注释

3 个答案: