SELECT SUBSTRING(m.content,1,20) as content,
m.viewed, m.sent_date,
u.username
FROM message m
INNER JOIN user u
ON u.userid = m.message_from
WHERE m.message_to = :userid
我对此查询的问题是它从同一用户名中选择多行。我只想让它为每个用户名选择一行。
我相信我使用DISTINCT?
我无法让它工作,有人可以帮助我!
感谢。
答案 0 :(得分:1)
SELECT SUBSTRING(m.content,1,20) as content, m.viewed, m.sent_date, u.username
FROM message m INNER JOIN user u ON u.userid = m.message_from
WHERE m.message_to = :userid GROUP BY u.userid
答案 1 :(得分:-1)
是的!您可以在用户名中使用distinct
SELECT Distinct( u.username ), SUBSTRING(m.content,1,20) as content,
m.viewed, m.sent_date
FROM message m
INNER JOIN user u
ON u.userid = m.message_from
WHERE m.message_to = :userid