Question

此代码用于将这些对象打印到名为 customer.txt 的文件中。它工作正常，但我试图设置条件，如果 balance＆gt; 3000 打印该对象。

如何宣布平衡？我应该读取余额的字节并打印出来吗？

 File a = new File("customer.txt");

 FileWriter v = new FileWriter(a);
 BufferedWriter b = new BufferedWriter(v);
 PrintWriter p = new PrintWriter(b);


 human Iman = new human("Iman", 5000);
 human Nour = new human("Nour", 3500);
 human Redah = new human("Redah", 0);
 human iman = new human("iman", 200);
 human MohamedREDA = new human("MohamedREDA", 3000);
 human Mohamed_Redah = new human("Mohamed Redah", 2000);

 human[] h = new human[6];

 h[0] = Iman;
 h[1] = Nour;``
 h[2] = Redah;
 h[3] = iman;
 h[4] = MohamedREDA;
 h[5] = Mohamed_Redah;

 p.println(Iman);
 p.println(Nour);
 p.println(Redah);
 p.println(iman);
 p.println(MohamedREDA);
 p.println(Mohamed_Redah);

 p.flush();
 }

 }
 class human {
     public String name;
     public double balance;

     public human(String n, double b) {
         this.balance = b;
         this.name = n;

     }@
     Override
     public String toString() {
         return name + " " + balance;
     }

Answer 1

更改逻辑如下：

遍历数组

for (int i = 0; i < h.length; i++){    
    if(h[i].balance>3000){
        p.println(h[i]);   
    }
}

如何制作平衡打印条件

1 个答案: