Question

我很难通过这个Guess The Number任务。我似乎无法做到正确，并希望得到一些帮助。再次播放选项无法正常工作，因为当您赢得游戏并选择是再次播放时，它不会重新启动游戏，它将继续您的下一个猜测数字（例如：猜测数字1，猜测数字2 ......）。但是当你输了它时会回到第一部分，它会问你“想要多少次尝试”。那么我怎样才能获得胜利的部分呢？另外，有人可以给我一些关于如何改进提示选项的提示吗？另外，我是否需要插入任何 def main（）：的东西？因为我不确定我们是否已经完成了这项任务。所以请帮帮我。感谢。

# This is a guess the number game.
import random
answer = "yes"
number = random.randint(1, 10)

while answer == 'yes':
    tries = 0
    guess = 0
    guessnumber = 0
    tries = int(input("How many tries would you like? "))
    tries2 = tries
    while guessnumber != tries2:
            guessnumber += 1
            guess = int(input("Enter guess number " + str(guessnumber) + ": "))
            if guess < number:
                print("You guessed too low")
                hint = input("Would you like a hint, yes or no?: ")
                if hint == "no":
                    continue
                    print("The number is less than", number + 1)
                if guess > number:
                    print("You guessed too high")
                    hint = input("Would you like a hint, yes or no?: ")
                    if hint == "no":
                        continue
                    print("The number is greater than", number - 1)
                if guess == number:
                    tries = str(tries)
                    print("YOU WON!")
                    answer = input("Play again? Yes/No? ") `enter code here`
                    if answer == 'no':
                        break
            if guess != number:
                number = str(number)
                print("GAME OVER!!! The number I was thinking of was " + number)
                answer = input("Play again? Yes/No? ")
                if answer == "no":
                    break

Answer 1

最简单的方法是使用函数。这是一些可能的伪代码：

def game():
    tries = 0
    guess = 0
    ...
    if guess != number:
        number = str(number)
        print("GAME OVER!!! The number I was thinking of was " + number)

 answer = "yes"
 while answer == 'yes':
     game()
     answer = input("Play again? Yes/No? ")

功能有助于将问题分解为更小和更易维护的部件。

对于此代码，您肯定可以在代码中重置变量，但不建议这样做。

P.S。它可以理解它是什么游戏，但更好的写入描述，而不只是写“赋值”。更明确的问题是，你更有可能得到答案。

Answer 2

有几件事：

random.randint（1,1）表示产生1到1之间的随机整数。它总是给出1。

为什么只设置一次“尝试”副本？

Python MATTERS中的缩进。它会更改if / elif / else分支的计算方式。因此（猜测＆gt;数字）和（guess == number）检查是以（猜测＆lt;数字）为条件的，这是不可能的。鉴于这些状态：（guess＆lt; number），（guess＆gt; number）和（guess == number）相互排斥并比较相同的变量，最好将后续if块更改为elifs。

“GAME OVER”应该只在尝试用尽后触发，因此它不能在（guessnumber＆lt; attempts）循环内。

# This is a guess the number game.
import random
answer = "yes"
number = random.randint(1, 100)

while answer != 'no':
    guess = 0
    guessnumber = 0
    tries = int(input("How many tries would you like? "))
    while guessnumber < tries:
            guessnumber += 1
            guess = int(input("Enter guess number " + str(guessnumber) + ": "))
            if guess < number:
                print("You guessed too low")
                hint = input("Would you like a hint, yes or no?: ")
                if hint == "no":
                    continue
                print("The number is less than", number + 1)
            elif guess > number:
                print("You guessed too high")
                hint = input("Would you like a hint, yes or no?: ")
                if hint == "no":
                    continue
                print("The number is greater than", number - 1)
            elif guess == number:
                print("YOU WON!")
                answer = input("Play again? Yes/No? ") #enter code here
                break
    if (guess != number) and (guessnumber >= tries):
        number = str(number)
        print("GAME OVER!!! The number I was thinking of was " + number)
        answer = input("Play again? Yes/No? ")

在Guess中重新启动选项Python中的数字

2 个答案: