Question

我试图猜测python中的数字游戏，但每当我猜它重复4次＆＃39;你的猜测太低了＆＃39;

import random
number = random.randint(1, 20)
guessestaken = 0
print('I am thinking of a number between 1 and 20 ')
guess = raw_input('Take a guess and hit enter')
while guessestaken < 4:
    guessestaken = guessestaken + 1
    if guess > number:
        print('your number is too low')
    if guess < number:
        print('your number is too high ')
    if guess == number:
        break
        print('well done the number was ' + number + ' and you got it in ' + guessestaken + '')

Answer 1

您在while循环之前要求输入用户。

guess = int(raw_input('Take a guess and hit enter'))

此声明应位于while块内。

函数raw_input返回一个字符串，您应该将其转换为整数。您可以在Documentation。

中详细了解相关信息

Answer 2

在您进入循环之前，您只要求用户输入一次。在循环的每次迭代之后，您将需要询问用户新的输入，否则猜测将永远不会改变！

此外，当您使用raw_input读取用户的某些输入时，它将是一个字符串。您需要将其强制转换为int。接下来，如果循环中断，则不会调用它后面的语句。这意味着当用户得到正确的答案时，您需要将break语句移动到输出之后，否则将不会打印任何内容。最后，if语句中的逻辑是向后的，如果猜测小于你生成的数字，那么猜测太低，不会太高！总而言之：

import random
number = random.randint(1, 20)
guessestaken = 0
print('I am thinking of a number between 1 and 20 ')
while guessestaken < 4:
    guess = int(raw_input('Take a guess and hit enter'))
    guessestaken = guessestaken + 1
    if guess < number:
        print('your number is too low')
    if guess > number:
        print('your number is too high ')
    if guess == number:
        print('well done the number was ' + number + ' and you got it in ' + guessestaken + '')
        break

Answer 3

你需要让用户在你的循环中输入，否则你只是多次比较他的第一个猜测。此外，您应该将输入值转换为整数，因为raw_input返回一个字符串。

>>> guess = raw_input('guess the number> ') >>> type(guess) <type 'str'> >>> type(int(guess)) <type 'int'>

Answer 4

来自随机进口randint

print("you wanna guess a number between A to B and time of guess:")
A = int(input("A:"))
B = int(input("B:"))
time = int(input("time:"))
x = randint(1, 10)
print(x)

while time != 0:
    num = int(input("Enter: "))
    time -= 1
    if num == x:
        print("BLA BLA BLA")
        break
    print("NOPE !")
    if time == 0:
        print("game over")
        break

Python猜数字游戏

4 个答案: