为了清楚起见,我创建了一个要点,其中包含我所指的数据格式的示例:
https://gist.github.com/TestAcc7777/5823760
在其他一些不相关的数据之后,输出文件包含许多这些列表块,一个接一个,每次都重复标题部分。每个标题实例最多有八组读数,它们一起构成一个块。标题中的数量组织反映了后续读数的值的组织。
鉴于此,我需要提取标题中给出的一些数量的值,将它们放在一个带有相关数量的文件中,并使matplotlib绘制一组数量与另一个数量。例如eng_tot与时间(ps)。
我完全迷失了,因为这远远超出了我使用Python或matplotlib的经验,所以欢迎任何帮助。
答案 0 :(得分:0)
这不是一个完整的答案,但应该让你开始。
#!/bin/env python
import sys
import re
import pprint
# Some function that determines whether a line is a seperator
def is_sep(line):
return (line.count('-') > 80)
# Some function that parses the "block"
def parse_block(lines):
parsed_lines = []
for line in lines:
matches = re.findall('(\S+)', line)
parsed_lines.append(matches)
return parsed_lines
if __name__ == "__main__":
# Read in data
with open('data.txt', 'r') as fh:
data = fh.read()
# Split data into lines, then split the lines into "blocks"
blocks = []
block_lines = []
for line in data.splitlines():
if(is_sep(line)):
blocks.append(block_lines)
block_lines = []
else:
block_lines.append(line)
# This splitting method will create an empty "block" as the first element of the list, delete it
blocks = blocks[1:]
# For all blocks but the header block, pass it to "parse_block"
parsed_blocks = []
for block in blocks[1:]:
parsed_blocks.append(parse_block(block))
pprint.pprint(parsed_blocks[0])
例如,您数据的最后一个块将被解析为:
[['1', '2.6814E+03', '3.3117E+02', '1.6616E+03', '-1.1814E+02', '1.8312E+03', '3.5247E+03', '2.5879E+02', '-3.8350E+03', '0.0000E+00'],
['0.0', '2.5785E+04', '6.8687E+01', '-6.7273E+04', '-7.6310E+03', '-1.8316E+03', '-5.7811E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00'],
['4.9', '1.3300E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00', '9.0000E+01', '9.0000E+01', '9.0000E+01', '0.0000E+00', '1.1911E+02'],
[],
['rolling', '2.6814E+03', '3.3117E+02', '1.6616E+03', '-1.1814E+02', '1.8312E+03', '3.5247E+03', '2.5879E+02', '-3.8350E+03', '0.0000E+00'],
['averages', '2.5785E+04', '6.8687E+01', '-6.7273E+04', '-7.6310E+03', '-1.8316E+03', '-5.7811E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00'],
['1.3300E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00', '9.0000E+01', '9.0000E+01', '9.0000E+01', '0.0000E+00', '1.1911E+02']]